# Reasoning Quiz for IBPS| RRB – 327

1) Statements:
All watches are gold.
Some phones are gold.
All pens are phones.
Conclusions:
I. Some phones are watches.
II. Some pens are gold.
III. Some gold are watches.
IV. No pen is gold.
a) Only either II or IV and III follow
b) Only either II or IV and I follow
c) Only either I or II and IV follow
d) None follows
e) All follow

Answer a) Only either II or IV and III follow 2)Statements:
All tigers are keys.
Conclusions:
I. Some tapes are tigers.
II. Some tapes are keys.
III. No water is tape.
IV. All keys are tigers.
a) None follows
b) Both II and III follow
c) Only either II or III follows
d) Only either I or III follows
e) Only either I or IV follows 3) Statements:
Some bikes are buildings.
All buildings are bottles.
Some bottles are trucks.
Conclusions:
I. Some bikes are trucks.
II. Some bikes are bottles.
III. Some bottles are buildings.
IV. No truck is a bike.
a) None of the above
b) II and III only follow
c) Either only I or II and III and IV follows
d) Either only I or IV

Answer d) Either only I or IV 4) Statements:
No cards are lines.
All copies are cards.
All cards are telephones.
Conclusions:
I. Some lines are not copies.
II. Some copies are neither cards nor telephones.
III. Some telephones are neither copies nor cards.
IV. Some copies are not radios.
a) Only I follow
b) Only IV follows
c) Only I and IV follow
d) All follows
e) None of these

Answer c) Only I and IV follow 5)  Statements:
Some umbrellas are sticks.
Some sticks are balls.
Some balls are bats.
All bats are guns.
Conclusions:
I. Some balls are umbrellas.
II. Some guns are bats.
III. Some sticks are guns.
IV. Some balls are guns.
a) Only I, II and IV follow
b) Only II and IV follow
c) Only II, III and IV follow
d) Only I, II and III follow
e) None of these

Answer b) Only II and IV follow Directions (6-10): In a certain instruction system the different computation processes are written as follows:
(i) X \$ Y «Z means Z is subtracted from the product of X and Y.
(ii) X @ Y # Z means X is multiplied by the sum of Y and Z.
(iii) X l Y e Z means Z is subtracted from Y and the resultant is added to X.
(iv) X © Y % Z means Y is divided by Z and the resultant is added to square of X.
In each of the following questions, a set of instruction sequence is given. You are required to find out the outcome which should come in place of the question mark (?) in each of the given sets of sequence.

6) 17 \$ 4 « 8 = t
7 © t % 15 = ?
a) 11
b) 53
c) 13
d) 51

17 \$ 4 « 8
(17 × 4) – 8 [Use instruction (iii)] = 60
Hence t = 60
Now, we have
(60 ÷ 15) + 7^2 [Use instruction (ii)] = 53
? = 53

7) 13 @ 4 # 3 = p
p \$ 5 « 55 = ?
a) 45
b) 75
c) 340
d) 400

13 @ 4 # 3
13 × (4 + 3) [Use instruction (i)] = 91
Hence p = 91
Now, we have
91 \$ 5 « 55
(91 × 5) – 55 [Use instruction (iii)] = 400
?= 400

8) b \$ 15 « 18 = 42
b © 36 % 9 = ?
a) 12
b) 16
c) 20
d) 18

b \$ 15 « 18 = 42
(b × 15) – 18 = 42 [Use instruction (iii)] (b × 15) = 42 + 18
b = 4
Now, we have
(36 ÷9) + 4^2 [Use instruction (ii)] = 20
? = 20

9) 5 © 49 % 7 = a
a l 87 e 29 = ?
a) 118
b) 108
c) 98
d) 90

(49 ÷ 7) + 5^2 [Use instruction (ii)] = 32
Hence a = 32
Now, we have
32 l 87 e 29
(87 – 29) + 32 [Use instruction (iv)] = 58 + 32 = 90
?= 90

10) m l 78 e 56 = 50
m @ 7 # 13 = ?
a) 560
b) 56
c) 280
d) Cannot be determined

m l 78 e 56 = 50
(78 – 56) + m = 50 [Use instruction (iv)] m = 50 – 22 = 28
Now, we have
28 @ 7 # 13
28 × (7 + 13) [Use instruction (i)] = 560
? = 560