Quantitative Aptitude Quiz – 88

In Quantitative Aptitude, Quants & Reasoning
February 2, 2016

1. If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
a) 50 km
b) 56 km
c) 70 km
d) 80 km

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Ans: a) 50 km
Explanation:
Let the actual distance travelled be x km.
Then,
x /10 = (x + 20)/14
14x = 10x + 200
4x = 200
x = 50 km.

2. A, B and C jointly thought of engaging themselves in a business venture. It was agreed that A would invest Rs. 6500 for 6 months, B, Rs. 8400 for 5 months and C, Rs. 10,000 for 3 months. A wants to be the working member for which, he was to receive 5% of the profits. The profit earned was Rs. 7400. Calculate the share of B in the profit.
a) Rs. 1900
b) Rs. 2660
c) Rs. 2800
d) Rs. 2840

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Ans: b) Rs. 2660
Explanation:
For managing, A received = 5% of Rs. 7400 = Rs. 370.
Balance = Rs. (7400 – 370) = Rs. 7030.
Ratio of their investments = (6500 x 6) : (8400 x 5) : (10000 x 3)
= 39000 : 42000 : 30000
= 13 : 14 : 10
B’s share = Rs. (7030 x 14 / 37) = Rs. 2660.

3. On dividing a number by 357, we get 39 as remainder. On dividing the same number 17, what will be the remainder ?
a) 0
b) 3
c) 5
d) 11

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Ans: c) 5
Explanation:
Let x be the number and y be the quotient. Then,
x = 357 x y + 39
= (17 x 21 x y) + (17 x 2) + 5
= 17 x (21y + 2) + 5)
Required remainder = 5.

4. In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, what is the dividend ?
a) 4236
b) 4306
c) 4336
d) 5336

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Ans: d) 5336
Explanation:
Divisor = (5 x 46) = 230
10 x Quotient = 230 = 230 / 10 = 23
Dividend = (Divisor x Quotient) + Remainder
= (230 x 23) + 46
= 5290 + 46
= 5336.

5. The least perfect square, which is divisible by each of 21, 36 and 66 is:
a) 213444
b) 214344
c) 214434
d) 231444

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Ans: a) 213444
Explanation:
L.C.M. of 21, 36, 66 = 2772.
Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11
To make it a perfect square, it must be multiplied by 7 x 11.
So, required number = 2² x 3² x 7² x 11² = 213444

6-10: Study the following line graph and answer the questions.

6. For which of the following pairs of years the total exports from the three Companies together are equal?
a) 1995 and 1998
b)1996 and 1998
c) 1997 and 1998
d) 1995 and 1996

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Ans: d) 1995 and 1996

Explanation:
Total exports of the three Companies X, Y and Z together, during various years are:
In 1993 = Rs. (30 + 80 + 60) crores = Rs. 170 crores.
In 1994 = Rs. (60 + 40 + 90) crores = Rs. 190 crores.
In 1995 = Rs. (40 + 60 + 120) crores = Rs. 220 crores.
In 1996 = Rs. (70 + 60 + 90) crores = Rs. 220 crores.
In 1997 = Rs. (100 + 80 + 60) crores = Rs. 240 crores.
In 1998 = Rs. (50 + 100 + 80) crores = Rs. 230 crores.
In 1999 = Rs. (120 + 140 + 100) crores = Rs. 360 crores.
Clearly, the total exports of the three Companies X, Y and Z together are same during the years 1995 and 1996.

7. Average annual exports during the given period for Company Y is approximately what percent of the average annual exports for Company Z?
a) 87.12%
b) 89.64%
c) 91.21%
d) 93.33%

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Ans: d) 93.33%

8. In which year was the difference between the exports from Companies X and Y the minimum?
a) 1994
b) 1995
c) 1996
d) 1997

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Ans: c) 1996

9. What was the difference between the average exports of the three Companies in 1993 and the average exports in 1998?
a) Rs. 15.33 crores
b) Rs. 18.67 crores
c) Rs. 20 crores
d) Rs. 22.17 crores

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Ans: c) Rs. 20 crores