Quantitative Aptitude Quiz – 71 (Mixed)

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Welcome To D2G’s. To get a good score in the exams, it is very important to study in a proper way. Here we are posting a mixed Quantitative aptitude set with required explanations for your practice. Do not give up, the beginning is always the hardest. Keep learning.

1. A textile manufacturing firm employees 50 looms. It makes fabrics for a branded company. The aggregate sales value of the output of the 50 looms is Rs.5,00,000 and the monthly manufacturing expenses is Rs.1,50,000. Assume that each loom contributes equally to the sales and manufacturing expenses are evenly spread over the number of looms. Monthly establishment charges are Rs.75,000. If one loom breaks down and remains idle for one month, the decrease in profit is:
a) 9000
b) 14000
c) 7000
d) 3500
e) None of these

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Answer c) 7000
Explanation:
Profit = 5,00,000 – (1,50,000 + 75,000) = 2,75,000
When one breaks down, it will effect output value and manufacturing expenses. Fixed monthly charges won’t change.
New profit = (49/50) * (50000 – 150000) – 75000 = 268000
Decrease in profit = 7000.

2. One type of liquid contains 45% of milk, the other contains 25% of milk. A can filled with 7 parts of the first liquid and 3 parts of the second liquid. What is the percentage of milk in the new mixture?
a) 70
b) 35
c) 36
d) 39
e) 42

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Answer d) 39
Explanation:
Let the can contains 100 litres.
Quantity of milk = 70*(45/100) + 30*(25/100) = 31.5 + 7.5 = 39lt.
Then, % of milk = 39/100 * 100 = 39%.

3. A car travels a distance of 80 kms at the speed of 16 kmph. It covers the next 70 kms at the speed of 10 kmph and last 160 kms at the speed of 20 kmph. What is the average speed of the car?
a) 15
b) 15.5
c) 16
d) 16.5
e) 17.5

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Answer b) 15.5
Explanation:
T1 = 80/16 = 5hr, T2 = 70/10 = 7hr, T3 = 160/20 = 8hr
Distance = 80 + 70 + 160 = 310km,
Time = 5 + 7 + 8 = 20 hr
Avg. speed = 310/20 = 15.5.

4. In an election between two candidates, one got 72% of the total valid votes. 25% of the total votes are invalid. If the total votes are 8200, what is the number of valid votes the other person got?
a) 1853
b) 1722
c) 2050
d) 4428
e) None of these

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Answer b) 1722
Explanation:
Total valid votes = 8200 * 75/100 = 6150
Other person got = 6150 * 28/100 = 1722 votes.

5. The respective ratio of the number of boys to the number of girls studying in a school is 25 : 29. The total number of students studying in the school is 270. If 15 boys and 15 girls take admission in the school, what will be the new respective ratio of the boys and girls studying in the school?
a) 6 : 7
b) 8 : 9
c) 7 : 8
d) 7 : 9
e) None of these

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Answer c) 7 : 8
Explanation:
By short cut method,
(25 + 29) ~ 270 students
1 ~ 5 students
3 ~ 15 Boys/Girls
Hence, (25 + 15) Boys / (29 + 15) Girls = 28/32 = 7/8 = 7 : 8.

6. The total area of a circle and a square is equal to 5450 sq. cm. The diameter of the circle is 70 cm. What is the sum of the circumference of the circle and the perimeter of the square?
a) 360
b) 380
c) 270
d) Can’t be determined
e) None of these

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Answer b) 380
Explanation:
D = 70cm, R = 70/2 = 35cm
Area of a square + Area of a circle = 5450
=>a^2 + 22/7 * 35 * 35 = 5450
=>a^2 = 5450 – 3850 = 1600
=>a = 40
Then, Circumference of circle + Perimeter of square
=>2 * 22/7 * 35 + 4 * 40 = 220 + 160 = 380cm.

7. In a test, Rajesh got 112 marks which is 32 more than the passing marks. Sonal got 75% marks which is 70 more than the passing marks. What is the minimum passing percentage of the test?
a) 35
b) 45
c) 40
d) 30
e) None of these

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Answer c) 40
Explanation:
Let the total number be X.
According to question, X * 75% – 70 = 112 – 32
=>X * 75/100 = 80 + 70
=>X = (150 * 100) / 75 = 200 marks
passing marks = 200 * 75/100 – 70 = 80 marks
Minimum passing marks(in percentage) = 80/200 * 100 = 40%.

8. A car reached cuttack from bhubaneswar in 35 min with an average speed of 69 Km/h. If the average speed is increased by 36 Km/h. How much time will it take to cover the same distance?
a) 24 min
b) 27 min
c) 23 min
d) 29 min
e) None of these

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Answer c) 23
Explanation:
Total distance covered by car in 35 min = 69 * 35/60 = 161/4 Km
New speed of car = 69 + 36 = 105 Km/h
So, time taken by car to covered the same distance = {161 / (4*105)} * 60 = 23 min.

9. 4 examiners can examine a certain number of answer papers in 10 days by working for 5 hr a day. For how many hours in a day would 2 examiners have to work in order to examine twice the number of answer papers in 20 days?
a) 10
b) 9
c) 8
d) 17/2
e) None of these

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Answer a) 10
Explanation:
We know that,
M1D1H1 / W1 = M2D2H2 / W2
=>(4 * 10 * 5) / 1 = (2 * 20 * x) / 2
Therefore, x = 10h.

10. The average speed of a bus is 67 Km/h. The bus was scheduled to start at 12 pm. It was scheduled to reach a destination 335 Km away from its starting point at 7 Pm and a halt was scheduled on the way. For how long was the halt scheduled?
a) 3 hr
b) 2 hr
c) 1 hr
d) Can’t be determined
e) None of these

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Answer b) 2 hr
Explanation:
Time taken to covered the distance = 335/67 = 5 hr
Then, time of halt = Total time – 5 hr = (7 – 5) hr = 2 hr.

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D2G’s Team..


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