Quantitative Aptitude Quiz – 61(T ‘n W)

Hello Readers,
Welcome to D2G’s. This Quiz contains some important questions on Time and Work with explanation, which can be asked in coming IBPS clerk exams. Hope this helps you in your practice.

1. Three workers working all day can finish a work in 10 days. If one worker works only half the time the work will be finished in?
a) 16
b) 15
c) 12.5
d) 12

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Answer d) 12 days
Explanation:
Time = 3*10 / 2.5 = 12 days.

2. Four men and three women can do a job in 6 days. When five men and six women work on the same job, the work gets completed in 4 days. How long will a woman take to do the job, if she works alone on it?
a) 18
b) 36
c) 54
d) 72

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Answer c) 54 days
Explanation:
(4M + 3W)*6 = (5M + 6W)*4
=>4M = 6W or 2M = 3W
=>4M + 3W = 6W + 3W = 9W
According to question, 1W * D = 9W * 6
=>d = 54 days.

3. A Team of 30 men is supposed to do a work in 38 days. After 25 days, 5 more men were employed and work was finished one day earlier. How many days would it have been delayed if 5 more men were not employed?
a) 1
b) 3
c) 4
d) 2

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Answer a) 1 day
Explanation:
Total time = 38-1 = 37,
35 men do rest of the work in (37-25) = 12 days,
This work will be done by 30 men in = D = 35*12 / 30 = 14 days
=>Total time = 25 + 14 = 39
=>One more day would be required.

4. Ajay can do 1/4th of the work in 3 days. Sunil can do 1/6th the same work in 4 days. How much will Ajay get if both work together and get paid Rs.180 in all?
a) 120
b) 108
c) 36
d) 60

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Answer a) 120
Explanation:
Ajay will do W work in 4*3 = 12 days,
Sunil will do W work in 6*4 = 24 days
Ratio of time taken = 1:2
=>Ration of Efficiences = 2:1 (days is inversely proportional to efficiencies)
Money is divided in the ratio of efficiencies
=>Ajay’s share = 2/3 * 180 = 120.

5. A certain job was assigned to a group of men to do in 20 days. But 12 men did not turn up for the job and remaining men did the job in 32 days. The original number of men in the group was?
a) 32
b) 34
c) 36
d) 40

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Answer a) 32
Explanation:
x*20 = (x-20)*32
=>x = 32.

6. A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?
a) 40
b) 50
c) 54
d) 60

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Answer d) 60 days
Explanation:
30 days work = w=>20 days work is 2W / 3, left = 1/3 W
1/3 W completed by A in 20 days
=>W work done in 20*3 = 60 days.

7. A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
a) 30
b) 40
c) 24
d) 60

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Answer d) 60 days
Explanation:
A + B = 1/30
16A + 44B = 1 =>16(1/30) + 28B = 1
=>28B = 1 – 16/30 = 14/30
=>B = 1/60 or B takes 60 days.

8. A, B and C can do a piece of work in 18, 24 and 36 days, respectively. They work alternately, first C, second day B and third day A, forth day C and so on. How many days will be needed to complete the work like this way?
a) 18
b) 20
c) 24
d) 30

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Answer c) 24 days
Explanation:
Work done in first 3 days,
= 1/18 + 1/24 + 1/36 = 1/8
So, Time taken to complete 1/8 part of work = 3 days
Then, Time taken to complete the whole work = 3*8 = 24 days.

9. 4 men or 6 women or 10 children can paint a house in 5 days. The painting is given to a couple and their 5 sons. They finish the job in how many days?
a) 11/60
b) 60/11
c) 61/11
d) 56/5

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Answer b) 60/11 days
Explanation:
4 men = 6 women = 10 children
=>1 men = 5/2 children
1 women = 5/3 children
Now, 1 couple + 5 children
= 1 men + 1 women + 5 children
=> (5/2 + 5/3 + 5) = 55/6 children
According to the formula,
M1 * D1 = M2 * D2
=>10*5 = 55/6 * D2 =>D2 = 60/11.

10. If 3 men and 4 boys can do a piece of work in 8 days, then 6 men and 8 boys can do the same work in:
a) 2
b) 4
c) 6
d) 16

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Answer b) 4 days
Explanation:
Let the men do the work in A days and the boys in B days
According to question,
3/A + 4/B = 1/8
Now, 6/A + 8/B = 2(3/A + 4/B) = 2 * 1/8 = 1/4
So, 6 men and 8 boys can do the same work in 4 days.
Best Wishes,

D2G’s Team


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