Quantitative Aptitude Quiz- 59 (Mixed)

Hello Aspirants,
Welcome to D2G’s. This post contains some important quantitative aptitude quiz based on clerical level. Practice makes a man perfect. Keep practicing, Keep shining.

1. In a park, there are some cows and some ducks. If total number of heads in the park are 68 and number of their legs together is 198, then find the number of ducks in the park.
a)32
b)37
c)35
d)31

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Answer b) 37
Explanation:
By using shortcut formula,
Here, L= 198 and H= 68
So, number of cows
= (L-2H)/2= (198-2*68)/2= 31
Now, number of ducks
= Number of heads-Number of cows= 68-31= 37

2. Find the maximum number of trees which can be planted 20m apart on the two sides of a straight road 1760m long.
a)174
b)176
c)180
d)178

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Answer d) 178
Explanation:
Number of trees that can be planted on one side of road
= (1760/20)+1= 88+1= 89
Then, trees on the both sides= 2*89= 178

3. A cricketer scored some runs in his continuous 9th innings. He scored 100 runs in his 10th innings and increases his average by 8 runs. What was the average of his runs at the end of 10th innings?
a)20
b)24
c)28
d)32

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Answer c) 28
Explanation:
Let,the average of a innings = x
Total runs= 9x
According to the question,
(9x+100)/10= x+8
=>9x+100= 10x+80
=>x= 20
Average after 10 innings= 20+8= 28

4. Aryan got 350 marks and vidya scored 76% marks in the same test. If vidya scored 296 marks more than Aryan, then what were the maximum marks of the test?
a)650
b)900
c)850
d)950

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Answer c) 850
Explanation:
Let the maximum marks of the exam is x.
According to the question,
Marks obtained by vidya= Marks obtained by Aryan+296
=>x*(76/100)= 350+296=>x*(76/100)= 646
=>x= (646*100)/76=>x= 8.5*100= 850
=>x=850

5. On selling an article at Rs.530, the gain is 20% more than the loss incured on selling it at Rs.475. in order to gain 20%, the selling price will be?
a)900
b)600
c)700
d)500

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Answer b) 600
Explanation:
Let CP= x
Then, according to the question,
(120/100)(x-475)= (530-x)
=>(6/5)(x-475)= (530-x)
=>6x-2850= 2650-5x
=>x= 500
Then, required SP= 500*(120/100)= Rs.600

6. P and Q entered a partnership for 3yr. At the start of the business, they invested Rs.13000 and Rs.25000, respectively. At the end of 3yr their total profit was Rs.76000. What will be share of Q out of this profit?
a)Rs.50000
b)Rs.26000
c)Rs.55000
d)Rs.21000

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Answer a) 50000
Explanation:
P’s share:Q’s share= Ratio of their investments
= 13000 : 25000= 13 : 25
Therefore, Q’s share= 25/(13+25)*76000
= (25/38)*76000= Rs.50000

7. Three Taps A,B and C fill a tank in 20min, 15min and 12min, respectively. If all the taps are opened simultaneously, how long will they take to fill 40% of the tank?
a)1min
b)2min
c)3min
d)4min

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Answer b) 2min
Explanation:
Part of the tank filled in 1min by A,B & C
= 1/20 + 1/15 + 1/12 = 1/5
Now, time taken by all pipes to fill the tank= 5min
Then, time taken by all three pipes to fill 40% of the tank
=> 40% of 5 = 2min

8. A certain distance is covered at a certain speed. If half of the distance is covered in double time, the ration of the two speeds is:
a)4:1
b)1:4
c)1:2
d)2:1

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Answer a) 4:1
Explanation:
Let, x km distance be covered in y hr.
So, speed in first case= x/y km/h
and speed in second case= (x/2)/2y= x/4y km/h
Required ratio= x/y : x/4y = 1:1/4 = 4:1

9. Two trains of lenghts 70m and 90m are moving in opposite directions at 10 m/s and 6 m/s, respectively. Find the time taken by trains to cross each other:
a)10s
b)8s
c)12s
d)16s

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Answer a) 10s
Explanation:
According to the formula,
Required time= (x+y)/(u+v)
Therefore, Required time= (70+90)/(10+6)= 160/16 = 10s

10. A wheel makes 4000 revolutions in moving a distance of 44km. Find the radius of the wheel?
a)15m
b)27m
c)1.75m
d)28m

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Answer c) 1.75m
Explanation:
Distance covered in 1 revolution= (44*1000)/4000 = 11m
According to question,
2*pie*r = 11 =>44/7 * r= 11
=>r= (11*7)/44= 1.75

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