Quantitative Aptitude Quiz for IBPS | IPPB – Set 185

In Quantitative Aptitude, Quants & Reasoning
January 29, 2017

1)3 years ago, the average of a family of 5 members was 17 years. A baby having been born, the average age of the family is the same today. The present age of the baby is?
A)5 years
B)2 years
C)1 year
D)4 years
E)None of these

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Answer B)2 years
Total age of 5 members, 3 years ago = (17 x 5) years = 85 years
Total age of 5 members now = (85 + 3 x 5) years = 100 years
Total age of 6 members now = (17 x 6) years = 102 years
Age of the baby = (102 – 100) years = 2 years

2)Of the four numbers, the first is twice the second, the second is one-third of the third and the third is 5 times the fourth. The average of the numbers is 24.75. The largest of these numbers is?
A)45
B)25
C)30
D)45
E)None of these

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Answer D)45
Let the fourth number be a
then hen, third number = 5a, second number= 5a/3 and first=10a/3
a+ 5a+ 5a/3 + 10/3 = 24.75 x 4
so,a=9
So, the numbers are 9, 45, 15 and 30

3)The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ratio of the number of boys to the number of girls in the class is?
A)1 : 4
B)2 : 3
c)3 : 4
D)4 : 2
E)None of these

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AnswerB)2 : 3
Let the ratio be k:1
Then, k x 16.4 + 1 x 15.4 = (k + 1) x 15.8
(16.4 – 15.8) k = (15.8 – 15.4)
k=2/3

4)The average price of 10 books is Rs. 12 while the average price of 8 of these books is Rs. 11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?
A)Rs 10 and Rs 16
B)Rs 12 and Rs 24
C)Rs 24 and Rs 18
D)Rs 28 and Rs 12
E)None of these

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Answer A) Rs 10 and Rs 16
Total price of the two books = Rs. [(12 x 10) – (11.75 x 8)] = Rs. (120 – 94) = Rs. 26
Let the price of one book be Rs.x
Then, the price of other book = Rs. (x + 60% of x )= x + (3/5)x= (8/5)x
so, x +(8/5)x=26 , x=10

5)The prices of the two books are Rs. 10 and Rs. 16
The average age of 30 boys of a class is equal to 14 years. When the age of the class teacher is included the average becomes 15 years. Find the age of the class teacher?
A)50
B)44
C)45
D)42
E)None of these

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Answer C)45
Total ages of 30 boys = 14 x 30 = 420 years
Total age when class teacher is included = 15 x 31 = 465 years
Age of class teacher = 465 – 420 = 45 years.

6)The average age of the group having 3 members is 84. One more person joins the group and now the average becomes 80. Now a fifth person comes whose age is 3 years more than that of fourth person replaces the first person. After this the average age of the group becomes 79. What is the weight of the first person?
A) 75
B) 65
C) 68
D) 82
E) 85

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Answer A) 75
Let the ages of these are A, B, C, D, E
So A+B+C = 84*3 = 252
And A+B+C+D = 80*4 = 320
So D = 320-252 = 68, so E = 68+3 = 71
Now B+C+D+E = 79*4 = 316
(A+B+C+D) – (B+C+D+E) = 320- 316
So A-E = 4, so A = 71+4

7)3 years ago, the average age of A, B, and C was 27 years. Also 5 years ago, the average age of B and C was 20 years. What is the present age of A?
A) 42
B) 40
C) 34
D) 35
E) 48

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Answer B) 40
Sum of ages of A+B+C 3 yrs ago = 27*3 = 81
So after 3 yrs, i.e. at present their total = 81 + 3*3 = 90
Similarly sum of present age of B&C = 20*2 +5*2 = 50
So present age of A = 90-50

8)Average age of girls in a class is 16 years. If the average of the boys in class is also added, the average becomes 15.5 years. If there were 20 boys in the class with average age 15 years, how many girls were there in the class?
A) 15
B) 40
C) 20
D) 25
E) 30

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Answer C) 20
Let x girls in the class, so
16x + 20*15 = 15.5 (x+20)

9)In a class, the average marks got by number of students in English is 52.25. 25% students placed in C category made the average of 31 marks, while 20% who were placed in A category made the average of 80 marks. Find the average marks of the remaining students?
A) 50
B) 52.2
C) 51
D) 51.8
E) 48.8

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Answer D) 51.8
Let there are 100 students in the class, then in category A = 20 students, in C = 25 students, remaining = 55 students. Let x be the average of these 55 students.
So 20*80+ 25*31 + 55*x = 52.25*100

10)The average of 5 numbers is 40. Average of first two and last two is 25 and 45 respectively. Find the middle number?
A) 60
B) 45
C) 30
D) Cannot be determined
E) None of these

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Answer A) 60
5*40 – (2*25 + 2*45)