Quantitative Aptitude Quiz for IBPS | IPPB – Set 178

1)872,872, 888, 824, ?, 692
1)712
2)846
3)723
4)692
5)None of these

Click to View Answer
Answer 1)712
872 – 02 = 872
872 + 42 = 888
888 – 82 = 824
824 + 122 = 968
968 – 162 = 712

2)69, 84, 189, ?, 1197, 2484
1)893
2)761
3)504
4)920
5)None of these

Click to View Answer
Answer 3)504
69+(1*3*5) = 84
84+(3*5*7) = 189
189+(5*7*9) = 504
504+(7*9*11) = 1197
1197+(9*11*13) = 2484

3)156, 173, 131, 181, 94, ?
1)321
2)89
3)171
4)255
5)None of these

Click to View Answer
Answer 4)255
156+17*1 = 173
173-21*2 = 131
131 + 25*3 = 206
206-29*4 = 90
90+33*5 = 255

4)980, 191, ?, 253, 504, 505
1)676
2)876
3)768
4)534
5)None of these

Click to View Answer
Answer 3)768
980÷5 -5 = 191
191*4+4 = 768
768÷3-3 = 253
253*2-2 = 504
504*1+1 = 505

5)33, 165, 825, ? , 20625
1)3625
2)4125
3)5225
4)6225
5)None of these

Click to View Answer
Answer 2)4125
33*0.5÷0.1 = 165
165*1÷0.2 = 825
825*1.5÷0.3 = 4125
4125*2÷0.4 = 20625

6)After measuring 100m of a rope, it was discovered that the metre rod was 2cm longer. The true length of the rod is?
1)95m
2)98m
3)96m
4)93m

Click to View Answer
Answer 2)98m
100*2 = 200cm measured long
Correct length = 100 – (200/100) = 100 -2 = 98m

7)A circle is drawn circumscribing a rectangle of sides 8cm and 6cm, find the area of the circle?
1)78.5cm2
2)82.7cm2
3)65.4cm2
4)54.9cm2

Click to View Answer
Answer 1)78.5cm2
Diagonal of rectangle = Diameter of circle
Diameter = √ (64+36) = 10
Radius = 5cm
Area of circle = 3.14*5*5 = 78.5cm2

8)If the sides of a equilateral triangle is increased by 10% , 30%and 60%then a new triangle is formed. By what % perimeter of the triangle is increased ?
1)40.50%
2)32.45%
3)33.33%
4)35.67%

Click to View Answer
Answer 3)33.33%
Let a = side of the triangle
Perimeter = 3a
New perimeter = a*110/100 + a*130/100 + a*140/100
= a(11+13+16)/10 = 4a
% increased in perimeter = (4a – 3a/3a)*100
= 100/3 = 33.33%

9)The side of a cube is 13 cm, Find its surface area?
1) 1014cm2
2) 1040cm2
3) 1010cm2
4) 1024cm2

Click to View Answer
Answer 1) 1014cm2

10)Explanation :Surface area = 6a2 = 6*13*13 = 1014cm2
The length of box 12 Cm long, 6 Cm breadth and 4Cm height. Find the maximum length of scale in that box?
1)11
2)14
3)12
4)9

Click to View Answer
Answer 2)14
Diagonal = √l2+b2+h2
= √122+62+42
= √196 => 14 Cm

Check out our latest videos on youtube