# Quantitative Aptitude Quiz for IBPS | IPPB – Set 194

1)A boat can travel 4.2km upstream in 14min. If the ratio of the speed of the boat in still water to the speed of the stream is 7:1. How much time will the boat take to cover 17.6km downstream ?
A)56min
B)44min
C)32min
D)48min
E)None of these

Speed = 7x:x
Downstream = 8x; upstream = 6x
Upstream speed = 4.2*60/14 = 18kmph
6x = 18
X = 3
Downstream = 8*3 = 24
Time taken for 17.6km = 17.6*60/24 = 44min

2) A man can row at 4 kmph in still water. If the velocity of the current is 1 kmph and it takes him 1 hour to row to a place and come back. how far is that place?
A)1.8km
B)2.6km
C)1.5km
D)3.2km
E)None of these

Let the distance is x km
Rate downstream = 4 + 1 = 5 kmph
Rate upstream = 4 – 1 = 3 kmph
then
x/5 + x/3 = 1
3x + 5x = 15
x = 15/8 = 1.8 km

3)Arun takes thrice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of the boat in still water and stream is?
A)3:1
B)1:2
C)2:1
D)2:3
E)None of these

speed downstream = x kmph
Speed upstream = 3x kmph
(3x+x)/2 : (3x-x)/2
4x/2 : 2x/2 = 2:1

4)A boat takes 30 hours for travelling downstream from point A to point B and coming back to point C midway between A and B. If the velocity of the stream is 2 kmph and the speed of the boat in still water is 15 kmph, what is the distance between A and B?
A)342km
B)356km
C)316km
D)308km
E)None of these

velocity of the stream = 2 kmph
Speed of the boat in still water is 15 kmph
Speed downstream = (15+2) = 17 kmph
Speed upstream = (15-2) = 13 kmph
Let the distance between A and B be x km
x/17+(x/2)/13=30
x/17+x/26=30
43x/442=30
x=30*442/43 = 308.37 = 308km
distance between A and B = 308 km

5)A boat takes 120min less to travel 30km downstream than to travel the same distance upstream.If the speed of the boat in still water is 8kmph then the speed of the stream is?
A)2kmph
B)8kmph
C)3kmph
D)4kmph
E)None of these

Speed of the stream = x
(30/8-x) – (30/8+x)= 120/60 = 2/1
30(8+x) – 30(8-x) = 2[64 – x2] 240+30x-240x+30x = 2[64 – x2] 60x = 128- 2×2
2×2+60x-128 = 0
x2+30x-64 = 0
(x+32)(x-2) = 0
X=2kmph

6)A train 250m long takes 30s to cross a man running at a speed of 6kmph in the direction opposite to that of train. What is the speed of the train?
A)20kmph
B)22kmph
C)23kmph
D)24kmph

Speed = x
Relative speed = (x+6)kmph
(x+6) = ( 250×18)/(30×5)
(x+6) = ( 4500)/(150)
X+6 = 30
X = 30 – 6 = 24kmph

7)A train 350m long takes 35s to cross a man running at a speed of 5kmph in the direction same to that of train. What is the speed of the train?
A)40kmph
B)41kmph
C)42kmph
D)43kmph

Speed = x
Relative speed = (x-5)kmph
(x-5) = ( 350×18)/(35×5)
(x-5) = ( 6300)/(175)
X-5 = 36
X = 36 + 5 = 41kmph

8)Without stopping the speed of the train is 120kmph , with stopping the speed of the train is 80kmph.Find the stop time of the train ?
A)10m
B)15m
C)20m
D)25m

Stopping time = (120 – 80 )/ 120 = 40/120 =1/3h
= 60/3 = 20 min

9)A train 160m long passes a standing man in 25s. What is the speed of the train ?
A)21kmph
B)23kmph
C)25kmph
D)27kmph

Speed = (160×18)/(25×5)
= 2880/125 = 23.04 = 23kmph

10)Two trains approach each other at 20kmph and 24kmph from 2 places 240km apart. After how many hours they will meet ?
A)5hrs
B)5.25hrs
C)5.30hrs
D)5.45hrs

20x + 24x = 240
44x = 240
X = 240/44 = 5.45hrs