# Quantitative Aptitude Quiz for IBPS | SBI – Set 220

1) To do a certain piece of work B would take three times as long as A and C together and C twice as long as A and B together. The three men by their united exertions can complete the work in 10 days. How long would each take by himself?

a)20, 30, 30
b)24, 40, 30
c)24, 30, 25
d)30, 40, 20

According to the question, 3 times B’s daily
work = (A + C)’s daily work.
Add B’s daily work to both sides.
4 times B’s daily work = (A + B + C)’s daily work = 1/10
B’s daily work = 1/40 …. (1)

Also, 2 times C’s daily work = (A + B)’s
daily work.
Add C’s daily work to both sides.
3 times C’s daily work = (A + B + C)’s daily work = 1/10

so, C’s daily work = 1/30…. (2)
Now A’s daily work 1/10 -(1/40+1/30) = 1/24 …. (3)
A, B and C can do the work in 24, 40
and 30 days respectively.

2)Mohan and Sohan working separately can dig a trench in 10 days and 12 days respectively. If they are working for 1 day alternately, Mohan beginning, in how many days will the trench be dug?
a)10 days
b)10 2/6 days
c)10 5/6 days
d)none of these.

Mohan’s 1 day’s work = 1/10
Sohan’s 1 day’s work = 1/12
(Mohan and Sohan)’s 10 days’ working
alternately = 5*1/10 + 5*1/12 = 11/12
Remaining work = 1/12
Now 1/10 of work done by Mohan in 1 day.
so, 1/12 of the work done by Mohan in 1 × 10 × 1/12 days = 5/6 days
Hence, trench will be dug in
=10+5/6== 10 5/6 days.

3) A certain number of men can do a work in 60 days. If there were 8 men more it could be finished in 10 days less. How many men are there?
a)42
b)40
c)30
d)45

The original number of men together with
8 men more can finish the work in (60 – 10 =) 50 days.
Now 8 men can do in 50 days what the original number of men can do in 10 days.
becoz In 50 days, a work is done by 8 men.
so, In 1 day, a work is done by (8 × 50) men.
so, In 10 days, a work is done by ( 8*50/10) = 40Men

4) 8 men and 12 boys can finish a piece of work in 10 days while 6 men and 8 boys can finish it in 14 days. Find the time taken by one man alone and that by one boy alone to finish the work?

a)280days , 140days
b)250days, 280days
c)300days, 200days
d)200days, 140days

5)If 9 men or 12 women or 18 boys can do a piece of work in 20 days working 9 hours a day, then working 10 hours a day in how many days will 3 men, 2 women and 3 boys together do twice
the work?
a)10boys
b)15boys
c)12boys
d)14boys

9 men = 18 boys
so, 1 man = 18/9 = 2 boys
Again, 12 women = 18 boys
so, 2 women = 18/12*2 = 3 boys
now 3 men + 2 women + 3 boys
= 6 + 3 + 3 = 12 boys

6)Number of students in Arts and Science faculties in an institute are in the ratio of 5 : 8 respectively. If 150 more students join
Art faculty while 80 more students join Science faculty, the respective ratio becomes 3 : 4. Originally what was the total
number of students in both faculties together ?
a) 1200
b) 1400
c) 1150
d) 1170

Let the original number of students in
Arts and Science faculties be 5x and 8x
respectively.
According to the question,
5x+150 /8x+80 = 3/4
= 24x+240 = 20x+600
4x= 360
x= 90
original number of students
5x+8x=
13x= 13*90 = 1170

7)If 6 engines consume 15 metric tones of coal when each is running 9 hours a day, how much coal will be required for 8 engines,
each running 12 hours a day, if being given that 3 engines of former type consume as much as 4 engines of latter type?
a) 20
b) 18
c) 27
d) 36

e= 4/3E
M1H1/W2 = M2H2/W2
8*9/15 = 8*12/W2
W2= 20

8)A tank is filled in 5 hours by three pipes A,B and C. The pipe C is twice as fast as Band B is twice as fast as A. How much time
will pipe A alone take to fill the tank?
a) 35hr
b) 30hr
c) 28hr
d) 26hr

C = 2B
B = 2A
A : B = 1 : 2
B : C = 1 : 2
Now, A : B : C
1: 2 : 4
A + B + C = 5h
7 = 5 h
1 = 35 hr
A = 35 hr

9)Prithvi spent RS89,745 on his college fees. RS51,291 on Personality Development Classes and the remaining 27% of the total
amount he had as cash with him. What was the total amount?
a) rs1,85,400
b) rs1,89,600
c) rs1,91,800
d) rs1,93,200

89745 + 51291
= 141036 = 73%
100% =141036/73 × 100
= 193200

10) In a class of 65 students and 4 teachers, each student got sweets that are 20% of the total number of students and each teacher
got sweets that are 40% of the total number of students. How many sweets were there?
a) 845
b) 897
c) 949
d) 104

65 students 4 teachers
Each students sweets = 65 ×1/5 = 13
Each teacher sweet = 65 × 65 ×2/5 = 26
Total no. of sweets = 13 × 65 + 26 × 4
= 845 + 104 = 949