In **Quantitative Aptitude** Section, **Boats & Streams** is very important. Increase your speed by practicing repeatedly.

**EXPLANATION GIVEN FOR EACH QUESTION. YOU CAN SEE THAT AFTER THE COMPLETION OF TEST.**

**Quick Test Details**

- Total Questions : 20
- Time : 20 Minutes
- Each Question Carries One Mark
- Topic :
**Boats & Streams**

#### Quiz-summary

0 of 20 questions completed

Questions:

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12
- 13
- 14
- 15
- 16
- 17
- 18
- 19
- 20

#### Information

QUICK TEST ON BOATS AND STREAMS

You have already completed the quiz before. Hence you can not start it again.

Quiz is loading...

You must sign in or sign up to start the quiz.

You have to finish following quiz, to start this quiz:

#### Results

0 of 20 questions answered correctly

Your time:

Time has elapsed

You have reached 0 of 0 points, (0)

Average score | |

Your score |

#### Categories

- Not categorized 0%
- Quantitative Aptitude 0%

**“CLICK VIEW QUESTIONS TO SEE THE EXPLANATION FOR EACH QUESTION“****Also Try Our Quick Tests With Clear Explanation****Quick Test on Time and Work****Quick Test on Time Speed Distance**

**SHARE THE TEST WITH YOUR FRIENDS!!!**

Pos. | Name | Entered on | Points | Result |
---|---|---|---|---|

Table is loading | ||||

No data available | ||||

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12
- 13
- 14
- 15
- 16
- 17
- 18
- 19
- 20

- Answered
- Review

- Question 1 of 20
##### 1. Question

Category: Quantitative AptitudeIf a man can swim downstream at 6kmph and upstream at 2kmph his speed in still water is

CorrectSpeed downstream a = 6 km ph

Speed upstream b = 2kmph

Speed in still water = ½ (a+b) kmph

= ½ (6+2)

= 8/2 = 4kmph

speed in still water = 4kmphIncorrectSpeed downstream a = 6 km ph

Speed upstream b = 2kmph

Speed in still water = ½ (a+b) kmph

= ½ (6+2)

= 8/2 = 4kmph

speed in still water = 4kmph - Question 2 of 20
##### 2. Question

Category: Quantitative AptitudeA man can row upstream at 8kmph and downstream at 12kmph the speed of the stream is

CorrectSpeed downstream a = 12kmph

Speed upstream b = 8 kmph

Speed of the stream = ½ (a-b) = ½ (12-8)

= 4/2 = 2 kmph

speed of the stream = 2kmphIncorrectSpeed downstream a = 12kmph

Speed upstream b = 8 kmph

Speed of the stream = ½ (a-b) = ½ (12-8)

= 4/2 = 2 kmph

speed of the stream = 2kmph - Question 3 of 20
##### 3. Question

Category: Quantitative AptitudeIf Anshul rows 15km upstream and 21km downstream taking 3 hours each time, then the speed of the stream is

Correctspeed upstream = 15/3 =5

b = 5km/hr

speed of the stream = ½ (a-b) km/hr

= ½ (7-5)

= 1 km/hr

speed of the stream = 1km/ hrIncorrectspeed upstream = 15/3 =5

b = 5km/hr

speed of the stream = ½ (a-b) km/hr

= ½ (7-5)

= 1 km/hr

speed of the stream = 1km/ hr - Question 4 of 20
##### 4. Question

Category: Quantitative AptitudeA man rows 750m in 675 seconds against the stream and returns in 7 ½ minutes. How rowing speed in still water is?

CorrectSpeed in still water = ½ (a+b)

= ½ (750/450 + 750/675 ) m /sec

= ½ (750/450 + 750/675 ) x 18/5 km/hr

= ½ (5/3 + 30/31) x 18/5 km/hr

= 4.7 km/hrIncorrectSpeed in still water = ½ (a+b)

= ½ (750/450 + 750/675 ) m /sec

= ½ (750/450 + 750/675 ) x 18/5 km/hr

= ½ (5/3 + 30/31) x 18/5 km/hr

= 4.7 km/hr - Question 5 of 20
##### 5. Question

Category: Quantitative AptitudeIf a boat goes 7km upstream in 42 minutes and the speed of the stream is 3kmph, then the speed of the boat in still water is

CorrectSpeed upstream = 7/42 km/min = 7/42 x 60 km/ hr

i.e, b=10 km/hr

Speed of the stream = 3km/hr

½ (a-b) = 3

½ (a-10) = 3 ==> a-10=6 ==>a=16 km/hr

Speed of the boat in still water

= ½ (a+b)

= ½ (16+10)

= 26/2 = 13km/hrIncorrectSpeed upstream = 7/42 km/min = 7/42 x 60 km/ hr

i.e, b=10 km/hr

Speed of the stream = 3km/hr

½ (a-b) = 3

½ (a-10) = 3 ==> a-10=6 ==>a=16 km/hr

Speed of the boat in still water

= ½ (a+b)

= ½ (16+10)

= 26/2 = 13km/hr - Question 6 of 20
##### 6. Question

Category: Quantitative AptitudeIf a man rows at 6kmph is still water and 4 : 5kmph against the current, then his along the current is

CorrectLet the rate along the current i.e, speed upstream b

Speed downstream b be x km/hr

a = 4.5km/hr

== > ½ (a+b) = 6

½ (4.5 + x ) = 6

4.5 + x = 12

x = 12 – 4.5 = 7.5

Speed along the current = 7.5 km/hrIncorrectLet the rate along the current i.e, speed upstream b

Speed downstream b be x km/hr

a = 4.5km/hr

== > ½ (a+b) = 6

½ (4.5 + x ) = 6

4.5 + x = 12

x = 12 – 4.5 = 7.5

Speed along the current = 7.5 km/hr - Question 7 of 20
##### 7. Question

Category: Quantitative AptitudeA man can row 9 1/3 kmph in still water and finds that it takes him thrice as much time to row up than as to row down the same distance in the river. The speed of the current is

CorrectLet man’s rate upstream be x km/hr. Then his rate downstream is 3 x km/hr

Speed in still water = 9 1/3 = 28/3 km/hr

i.e, ½ (a+b) = 28/3 km/hr

½ (x+3x) = 28/3

2x = 28/3 ==> x = 28/ 2 x 3 = 14/3 km/hr

Rate upstream b = 14/3 km/hr and

Rate downstream a = 14/3 x 3 = 14 km/hr

Speed of the current = ½ (a-b) = ½ (14 – 14/3)

= ½ (42-14/3) = 28/6 = 4 2/3 km/hrIncorrectLet man’s rate upstream be x km/hr. Then his rate downstream is 3 x km/hr

Speed in still water = 9 1/3 = 28/3 km/hr

i.e, ½ (a+b) = 28/3 km/hr

½ (x+3x) = 28/3

2x = 28/3 ==> x = 28/ 2 x 3 = 14/3 km/hr

Rate upstream b = 14/3 km/hr and

Rate downstream a = 14/3 x 3 = 14 km/hr

Speed of the current = ½ (a-b) = ½ (14 – 14/3)

= ½ (42-14/3) = 28/6 = 4 2/3 km/hr - Question 8 of 20
##### 8. Question

Category: Quantitative AptitudeA boat takes 4hours for traveling downstream from point A to point B and coming back to point A upstream. If the velocity of the stream is 2kmph and the speed of the boat in still water is 4kmph, what is the distance

between A and B?CorrectTime taken by boat to travel upstream and downstream = 4 hours

Velocity of the stream, ½ (a-b) = 2km/hr

a-b = 4km/hr ——- > 1

velocity of the boat in still water = ½ (a+b) = 4km/hr

a+b = 8 km/hr ——- > 2

solving 1 x 2 we get a = 6 km/hr b = 2km/hr

let the distance between A and B be x km

x / 2 + x / 6 = 4 ==> 3x + x / 6 = 4 ==> 4x = 24 ==> x = 6

Distance between A and B = 6kmIncorrectTime taken by boat to travel upstream and downstream = 4 hours

Velocity of the stream, ½ (a-b) = 2km/hr

a-b = 4km/hr ——- > 1

velocity of the boat in still water = ½ (a+b) = 4km/hr

a+b = 8 km/hr ——- > 2

solving 1 x 2 we get a = 6 km/hr b = 2km/hr

let the distance between A and B be x km

x / 2 + x / 6 = 4 ==> 3x + x / 6 = 4 ==> 4x = 24 ==> x = 6

Distance between A and B = 6km - Question 9 of 20
##### 9. Question

Category: Quantitative AptitudeSpeed of a boat in standing water is 9kmph and the speed of the stream is 1 : 5kmph. A man rows to a place at a distance of 10.5 km and comes back to the starting point. The total time taken by him is

CorrectSpeed in still water = ½ (a+b) = 9 kmph

= a+b = 18 ———- > (i)

Speed of the stream = ½ (a-b) = 1.5 kmph

= a-b = 3 kmph —— > (ii)

Solving (i) and (ii) gives a = 10.5km/hr ; b=7.5 kmph

Total time taken by him = 105/10.5 + 105/7.5 = 24 hoursIncorrectSpeed in still water = ½ (a+b) = 9 kmph

= a+b = 18 ———- > (i)

Speed of the stream = ½ (a-b) = 1.5 kmph

= a-b = 3 kmph —— > (ii)

Solving (i) and (ii) gives a = 10.5km/hr ; b=7.5 kmph

Total time taken by him = 105/10.5 + 105/7.5 = 24 hours - Question 10 of 20
##### 10. Question

Category: Quantitative AptitudeA man rows to a place 48km distant and back in 14 hours. He finds that he can row 4km with the stream in the same time as 3km against the stream. The rate of the stream is

CorrectSuppose he moves 4km downstream in x hours

Then, downstream a = 4 /x km/hr

Speed upstream b = 3/x km/hr

48 / 4 /x + 48 / 3/x = 14

x/4 + x/3 = 14/48 = ¼

3x + 4x / 12 = ¼ ==> 7x X 4 = 12 ==> x = 3/7

a=28/3 km/hr; b = 7km/hr

Rate of stream = ½ (28/3 – 7 )

= 7/6 = 1.1 km/hrIncorrectSuppose he moves 4km downstream in x hours

Then, downstream a = 4 /x km/hr

Speed upstream b = 3/x km/hr

48 / 4 /x + 48 / 3/x = 14

x/4 + x/3 = 14/48 = ¼

3x + 4x / 12 = ¼ ==> 7x X 4 = 12 ==> x = 3/7

a=28/3 km/hr; b = 7km/hr

Rate of stream = ½ (28/3 – 7 )

= 7/6 = 1.1 km/hr - Question 11 of 20
##### 11. Question

Category: Quantitative AptitudeA man rows to a place 48km distant and back in 14 hours. He finds that he can row 4km with the stream in the same time as 3km against the stream. The rate of the stream is

CorrectSuppose he moves 4km downstream in x hours

Then, downstream a = 4 /x km/hr

Speed upstream b = 3/x km/hr

48 / 4 /x + 48 / 3/x = 14

x/4 + x/3 = 14/48 = ¼

3x + 4x / 12 = ¼ ==> 7x X 4 = 12 ==> x = 3/7

a=28/3 km/hr; b = 7km/hr

Rate of stream = ½ (28/3 – 7 )

= 7/6 = 1.1 km/hrIncorrect

Then, downstream a = 4 /x km/hr

Speed upstream b = 3/x km/hr

48 / 4 /x + 48 / 3/x = 14

x/4 + x/3 = 14/48 = ¼

3x + 4x / 12 = ¼ ==> 7x X 4 = 12 ==> x = 3/7

a=28/3 km/hr; b = 7km/hr

Rate of stream = ½ (28/3 – 7 )

= 7/6 = 1.1 km/hr - Question 12 of 20
##### 12. Question

Category: Quantitative AptitudeA man swims at 16 kmph in still water. If the river is flowing at 5 kmph, it takes 10 hours to go upstream than to go to the same direction downstream. How far is the place? CorrectLet the distance be x km

Then, x/16 – 5 – x/16 + 5 = 10

x/11 – x/21 = 10

21x – 11x/21 X 11 = 10

∴ 21 X 11 = 231 kmIncorrectLet the distance be x km

Then, x/16 – 5 – x/16 + 5 = 10

x/11 – x/21 = 10

21x – 11x/21 X 11 = 10

∴ 21 X 11 = 231 km - Question 13 of 20
##### 13. Question

Category: Quantitative AptitudeA boat runs at 25 kmph along the stream and 10 kmph against the stream. Find the ratio of the speed of the boat in still water to that of the speed of the stream. CorrectSpeed along the stream = 25 kmph

Speed against the stream = 10 kmph

Now, the speed of the boat in still water = 25 + 10/2 = 17.5 kmph

Speed of stream = 25 – 10/2 = 7.5 kmph

∴ Reqd ratio = 17.5 : 7.5 = 7 : 3IncorrectSpeed along the stream = 25 kmph

Speed against the stream = 10 kmph

Now, the speed of the boat in still water = 25 + 10/2 = 17.5 kmph

Speed of stream = 25 – 10/2 = 7.5 kmph

∴ Reqd ratio = 17.5 : 7.5 = 7 : 3 - Question 14 of 20
##### 14. Question

Category: Quantitative AptitudeA boat covers a distance of 56 km downstream in 10 hours. To cover the same distance upstream, the boat takes 4 hours longer. What is the speed of the boat in still water? CorrectSpeed of the boat downstream = 56/10 = 5.6 kmph

Speed of the boat upstream = 56/14 = 4 kmph

Speed of the boat in still water = 5.6 + 4/2 = 9.6/2 = 4.8 kmphIncorrectSpeed of the boat downstream = 56/10 = 5.6 kmph

Speed of the boat upstream = 56/14 = 4 kmph

Speed of the boat in still water = 5.6 + 4/2 = 9.6/2 = 4.8 kmph - Question 15 of 20
##### 15. Question

Category: Quantitative AptitudeA man rows to a place 210 km away and comes back to the starting point. If the speed of the stream is 3 kmph and the speed of the boat in still water is 18 kmph, then what is the total time taken by him? CorrectTotal time = 210/(18 + 3) + 210/(18 – 3)

= 210/21 + 210/15 = 10 + 14 = 24 hoursIncorrectTotal time = 210/(18 + 3) + 210/(18 – 3)

= 210/21 + 210/15 = 10 + 14 = 24 hours - Question 16 of 20
##### 16. Question

Category: Quantitative AptitudeThe speed of a man in still water is 7.5 kmph and the rate of flow of water is 2.5 kmph. He takes 30 hours to row to a place and back. What is the distance between these two places? CorrectLet the distance between the two places be D km

Speed of the man downstream = 7.5 + 2.5 = 10 kmph

Speed of the man upstream = 7.5 – 2.5 = 5 kmph

Let the time taken to go downstream be t_{1}and upstream be t_{2}

Distance D is 10t_{1}= 5t_{2}

∴ t_{2}= 2t_{1}———— > (i)

t_{1}+ t_{2}= 30 ——— > (ii)

Solving (i) and (ii), we get

t_{1}= 10 hours

t_{2}= 20 hours

∴ Distance = 10t_{1}= 10 X 10 = 100 kmIncorrectLet the distance between the two places be D km

Speed of the man downstream = 7.5 + 2.5 = 10 kmph

Speed of the man upstream = 7.5 – 2.5 = 5 kmph

Let the time taken to go downstream be t_{1}and upstream be t_{2}

Distance D is 10t_{1}= 5t_{2}

∴ t_{2}= 2t_{1}———— > (i)

t_{1}+ t_{2}= 30 ——— > (ii)

Solving (i) and (ii), we get

t_{1}= 10 hours

t_{2}= 20 hours

∴ Distance = 10t_{1}= 10 X 10 = 100 km - Question 17 of 20
##### 17. Question

Category: Quantitative AptitudeA boat takes a total time of 11 hours and 15 minutes to travel a distance of 60 km upstream and 60 km downstream together. If the speed of the boat in still water is 12 kmph, what is the speed of the current? (in kmph) CorrectLet the speed of the current be x kmph

Then, download speed = 12 + x

Upstream speed = 12 – x

Now, 60/ 12 +x + 60/ 12 – x = 11 + 15/60 = 11¼ = 45/4

60 X 12 – 60x + 60 X 12 + 60x/144 – x^{2}= 45/4

1440/144 – x^{2}= 45/4

32/144 – x^{2}= ¼

128 = 144 – x^{2}

x^{2}= 144 – 128 = 16

∴ x = 4 kmphIncorrectLet the speed of the current be x kmph

Then, download speed = 12 + x

Upstream speed = 12 – x

Now, 60/ 12 +x + 60/ 12 – x = 11 + 15/60 = 11¼ = 45/4

60 X 12 – 60x + 60 X 12 + 60x/144 – x^{2}= 45/4

1440/144 – x^{2}= 45/4

32/144 – x^{2}= ¼

128 = 144 – x^{2}

x^{2}= 144 – 128 = 16

∴ x = 4 kmph - Question 18 of 20
##### 18. Question

Category: Quantitative AptitudeThe speed of a boat in still water is 20 kmph. If it can travel 52 km downstream and 28 km upstream in the same time, the speed of the stream is CorrectLet the speed of the stream be x kmph

Speed downstream = (x + 20) kmph

Speed upstream = (20 – x) kmph

∴ 52/ (20 + x) = 28/ (20 – x)

13/20 + x = 7/20 – x

260 – 13x = 140 + 7x

20x = 120

∴ x = 6 kmphIncorrectLet the speed of the stream be x kmph

Speed downstream = (x + 20) kmph

Speed upstream = (20 – x) kmph

∴ 52/ (20 + x) = 28/ (20 – x)

13/20 + x = 7/20 – x

260 – 13x = 140 + 7x

20x = 120

∴ x = 6 kmph - Question 19 of 20
##### 19. Question

Category: Quantitative AptitudeA boat takes 3 hours to travel from place A to place B downstream and back from B to A upstream. If the speed of the boat in still water is 4 kmph. What is the distance between the two places? CorrectLet the distance from place A to B be x km and the speed of the current be y km/hr

Now, x/4 + y + x/4 – y = 3

4x – xy + xy + 4x/(4 – y) (4 + y) = 3

3(16 – y^{2}) = 8x

48 – y^{2}= 8x

So, we can’t find the distances.IncorrectLet the distance from place A to B be x km and the speed of the current be y km/hr

Now, x/4 + y + x/4 – y = 3

4x – xy + xy + 4x/(4 – y) (4 + y) = 3

3(16 – y^{2}) = 8x

48 – y^{2}= 8x

So, we can’t find the distances. - Question 20 of 20
##### 20. Question

Category: Quantitative AptitudeThe total time taken by a boat travelling from X to Y and Y to X is 2 hours. The speed of the boat is 12 kmph and the distance between X and Y is 9 km. What is the speed of the current? CorrectLet the speed of the current be x kmph

Then, 9/12 + x + 9/12 – x = 2

9(12 – x + 12 + x)/144 – x^{2}= 2

24 X 9/144 – x^{2}= 2

144 – x^{2}= 108

x^{2}= 36

∴ x = 6 kmphIncorrectLet the speed of the current be x kmph

Then, 9/12 + x + 9/12 – x = 2

9(12 – x + 12 + x)/144 – x^{2}= 2

24 X 9/144 – x^{2}= 2

144 – x^{2}= 108

x^{2}= 36

∴ x = 6 kmph

** **

## Leave a Comment