# Quantitative Aptitude Quiz for IBPS | SBI – Set 216

Directions (Q. 1-5): Study the following graph carefully to answer the given questions.

Number of students writing IBPS, SSC and RRB from different institutes.

1)The total number of students writing RRB from all institutes together is approximately what per cent of the total number of students writing SSC from all institutes together?
a)80
b)70
c)85
d)79
e)75

Total number of students writing RRB from all institutes together
= 140 + 260 + 320 + 160 + 180 = 1060
Total number of students writing SSC from all institutes together
= 360 + 180 + 240 + 320 + 240 = 1340
Required % = 1060 / 1340 × 100
= 79.10
= 79%

2)The total number of students writing IBPS and RRB together from institute P is what per cent of the total number of students writing these two exams together from institute R?
a)61 2/13
b)68 4/13
c)69 3/13
d)65 7/13
e)64 5/13

Required %
= (Total number of students writing IBPS and RRB from Institute P / Total number of students writing IBPS and RRB from Institute R) × 100
= (140 + 220) / (200 + 320) × 100
= 360 / 520 × 100
= 900 / 13
= 69 3/13%

3)If out of the students writing SSC from institutes Q, S and T, 40%, 35% and 45% respectively got selected for SSC CGL tier 2, what is the total number of students who got selected for SSC CGL tier 2 from these three institutes together?
a)162
b)272
c)292
d)282
e)262

4)From institute P, out of the students writing IBPS, 40% got selected for Probationary Officer Interview, out of which 25% further got selected for Specialist Officer Interview. From institute T, out of the students writing IBPS, 45% got selected for Probationary Officer Interview, out of which two-thirds further got selected for Specialist Officer Interview. What is the total number of students writing IBPS from these two institutes who got selected for Specialist Officer Interview?
a)106
b)104
c)116
d)102
e)126

From Institute P the students writing IBPS selected for Specialist Officer Interview
= 220 × 40 / 100 × 25 / 100 = 22
From Institute T the students writing IBPS selected for Specialist Officer Interview
= 280 × 45 / 100 × 2 / 3 = 84
Total number of students selected for Specialist Officer Interview from Institute P and E together
= 22 + 84 = 106

5)If the number of students writing each exam in institute S is increased by 15% and the number of students writing each exam in institute Q is decreased by 5%, what will be the difference between the number of students in institute S and Q?
a)195
b)225
c)295
d)305
e)205

6)A man rows upstream 16 km and downstream 27 km talking 5 hours each time. What is the velocity of current?
a)2 km/hr
b)2.1 km/hr
c)1.1 km/hr
d)1.4 km/h
e)None of these

Answer c) 1.1 km/hr
Sol. Man’s rate upstream=16/5 km/hr
Man’s rate downstream=27/5 km/hr
Velocity of the current=1/2 (27/5-16/5) km/hr=1.1 km/hr

7)A boat moves downstream at the rate of 1 km in 6 minutes and upstream at the rate of 1 km in 10 minutes. The speed of the current is?
a) 2 km/hr
b) 1 km/hr
c) 1.5 km/hr
d) 2.5 km/hr
e) None of these

Answer a) 2 km/hr
Sol. D=60/6 =10 km/hr
U=60/10=6 km/hr
Y= 1/2 (10-6)=2 km/hr

8)In a recent opinion poll held during April, 60% of the respondents favoured India Against Corruption (IAC) while the rest favoured Indian political parties (IPP). It was found in May polls that 10% of IAC supporters switched their preference to IPP, while the same percentage of IPP’s supporters also switched their preference to IAC. What percentage of the electorate should now switch their preference from IAC to IPP so that they are equal?
a) 14%
b) 19%
c) 24%
d) 29%
e) None of these

Sol. Let the total number of respondents=100
People favoured IAC=60
People favoured IPP=40
New no. of people favouring IAC = 60+4-6 = 58
New no. of people favouring IPP = 40+6-4 = 42
Required percentage= (58-50)*100/58=14% Approx

Directions (9-10): For the two given equations I and II.
(a) If x is greater than y.
(b) If x is smaller than y.
(c) If x is equal to y.
(d) If x is either equal to or greater than y.
(e) If x is either equal to or smaller than y.

9)
I)6×2+5x+1=0
II)20y2+9y=-1

Sol. I)6×2+5x+1=0
(3x+1)(2x+1)=0
x=-1/3,-1/2
II)20y2+9y+1=0
(4y+1)(5y+1)=0
y=-1/4,-1/5= x<y

10) I)3×2+2x-1=0
II)2y2+7y+6=0

Answer a) If x is greater than y.
Sol. I)3×2+2x-1=0
(3x-1)(x+1)=0
x=1/3,-1
II)2y2+7y+6=0
(2y+3)(y+2)=0
y=-3/2,-2