Quantitative Aptitude Quiz for IBPS | SBI – Set 208

1)540, 272.5, ? , 141.25, 78.125, 49.06
A)160.25
B)141.25
C)90.50
D)210.75
E)None of these

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Answer B)141.25
(540+5)/2 = 272.5
(272.5+10)/2 = 141.25
(141.25+15)/2 = 78.125
(78.125+20)/2 = 49.0625

2)2340, 1172, 590, 301, ?
A)201.50
B)160.6
C)158.5
D)124.05
E)None of these

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Answer C)158.5
2340÷2 = 1170+2 = 1172
1172÷2 = 586+4 = 590
590÷2 =295+6 =301
301÷2 = 150.5+8 = 158.5

3)5, 136, ? , 8768, 88680
A)1032
B)1356
C)1562
D)2450
E)None of these

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Answer A)1032

4)19, 21, 45, 139, ?, 2811
A)1780
B)786
C)1290
D)561
E)None of these

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Answer D)561
19*1+2 = 21
21*2+3 = 45
45*3+4 = 139
139*4+5 = 561
561*5+6 = 2811

5)36, 19, 18, 28, 55, 138.5, ?
A)234.6
B)414.5
C)560.8
D)643.5
E)None of these

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Answer B)414.5
36*0.5+1 = 19
19*1 – 1 = 18
18*1.5+1 = 28
28*2-1 = 55
55*2.5+1 = 138.5
138.5*3-1 = 414.5

6)A Bus covers a distance of 36km at a uniform speed.Had the speed been 6 kmps less, it would have taken one hour more for the journey.The original speed of the bus is?
A)30kmps
B)12kmps
C)18mmps
D)20kmps

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Answer C)18kmps
36/(x-6) – 36/x = 1 X^2 – 6x – 216 = 0
x^2-18x+12x-216 = 0
(x+12)(x-18) = 0
X = 18kmph

7)Two buses of same length are running in in the same direction with speed 50km/hr and 80km/ph.The latter completely cross the man in 18sec. The length of the each bus is?
A)70m
B)75m
C)80m
D)150m

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Answer B) 75m
80 – 50 = 30
30×(5/18) = 25/3 m/s
Distance covered in 20sec = 18 ×(25/3) = 150
Length of each train = 150/2 = 75

8)A bus reached Mumbai from Hyderabad in 30min with an average speed of 50kmph. If the average speed is increased by 35kmph ,How long will it take to cover the same distance ?
A)17min
B)18min
C)19min
D)20min

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Answer B)18min
Time = [ 50 × (30/60) ] / (50 +35)
= [150/60] / 85
= 17.6 / 60 hr = 17.6 min = 18min

9)An aeroplane covers a certain distance at a speed of 240kmph in 5hours. To cover the same distance in 1(2/3) hours it must travel at a speed of?
A)700kmph
B)730kmph
C)720kmph
D)710kmph

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Answer C) 720kmph
D = 240×5 = 1200km
New speed = 1200/[5/3] = (1200×3) /5 = 720kmph

10)If Anil persons walks at 12kmph instead of 10kmph, he would have walked 18km more.The actual distance travelled by him is?
A)100km
B)90km
C)80km
D)60km

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Answer B) 90km
x/10 = (x+18)/12
12x = 10x + 180
2x = 180
X = 90km

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