**1) A and B can complete a piece of work in 8 and 10 days respectively. However, they work alternately, one day each, with A beginning the work. In how much time will the work be completed?**

a)8 4/7 days

b)8 2/5 days

c)8 3/5 days

D)8 4/5 days

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Answer D)8 4/5 days

Work of A and B for first 2 days = 1/8+1/10

= 9/40 of the whole of the work.

Work of A and B for 8 days = 8/2*9/40 of the whole of the work.

Remaining work after 8 days = 1-9/10= 1/10 of the whole of the work.

Since both A and B work alternately one day

each, with A beginning the work. It is the

turn of A for ninth day.

1/8 of the whole of the work is completed by A in 1 day.

so, Remaining 1/10 of the work will be

completed by A in 8/10 = 4/5 days

Hence the required time to complete the work = 8+4/5 = 8 4/5 days .

**2)A and B can polish the floors of a building in 25 days. A alone can do 1/3 of this job in 15 days. In how many days can B alone polish the floors of the building?**

a)56 1/4 days

b)58 1/4 days

c)56 3/4 days

d)50 1/4 days

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Answer a)56 1/4 days

It is given that A and B can polish the floors

of the building in 25 days.

Therefore, (A + B)’s 1 day’s work = 1/25

Now, A alone can do 1/3 of the work in 15 days.

so, A alone can do the complete work in

(3 × 15) = 45 days.

or, A’s 1 day’s work = 1/45.

Now, B’s 1 day’s work = (A + B)’s 1 day’s work

– A’s 1 day’s work = 1/25-1/45= 4/225

Hence, B alone can polish the floor in 4/225

days = 56 1/4 days .

**3) A can do a piece of work in 10 days and B in 20 days. They work together but 2 days before the completion of the work, A leaves. In how many days was the work completed?**

a) 9 days

b) 8 days

c) 10 days

d) 6 days

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Answer b) 8days

Suppose the work is finished in x days.

then , (x-2)/ 10 + x/20= 1

so, x= 8days .

**4)A and B can do a work in 45 and 40 days respectively. They began the work together, but A left after some time and B finished the**

** remaining work in 23 days. After how many days did A leave?**

a) 8 days

b) 10 days

c) 5 days

d) 9 days

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Answer d) 9 days

A alone can do the work in 45 days.

B alone can do the work in 40 days.

so, A’s 1 day’s work = 1/45

and B’s 1 day’s work = 1/40

(A + B) ’s 1 day’s work = 1/40+1/45= 40+45/ 40*45 .

Let after x days A left the work. Therefore, A

and B together worked for x days.

so, (A + B) ’s x days’ work = 85x /45*40

Again, B works alone for 23 days

so, Work done by B in 23 days = 23/40

Now, according to the question,

85x /45*40+ 23/40 = 1

x= 9 days.

**5)10 persons begin to work together on a job but after some days 4 persons leave. As a result, the job which could have been ****completed in 40 days is completed in 50 days. How many days after the commencement of the work did the 4 persons leave?**

a) 30 days

b) 22 days

c) 25 days

d) 35 days

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Answer c) 25 days

Suppose 4 persons leave after x days. It means

that 10 persons work for x days and (10 – 4 =)

6 persons work for (50 – x) days.

Then 40 days’ work done by 10 persons = x days’

work done by 10 persons + (50 – x) days’ work done by 6 persons.

or, 10 × 40 = 10x + 6(50 – x)

or, 4x = 100

or, x = 25 days.

**6)A match box measures 4 cm by 2.5 cm by 1.5 cm. What will be the volume of a packet containing 12 such match boxes? How many such packets can be placed in a card board box whose size is 60 cm × 30 cm × 24 cm?**

a) 240

b) 360

c) 580

d) 560

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Answer a)240

Volume of a match box = (4 × 2.5 × 1.5) cm3 = 15 cm3

= Volume of a packet containing 12 match boxes = (12 × 15) cm3 = 180 cm3.

Now, volume of card board box = (60 × 30 × 24) cm2 = 43200 cm3.

So, Number of packets that can be put in a

card board = 43200/180 = 240.

**7)To do a certain work B would take 3times as long as A and C together and C twice as long as A and B together . the 3 men by their united exertions can complete the work in 10 days . how long would each take by himself ?**

a)24,40,30,

b)50 ,20 ,60

c)24 , 40, 10,

d)30, 40, 10

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Answer a) 24,40,30

According to the question , 3times B’s daily work = (A+C)’s daily work

Add B ‘s work both side ,

then ,

4times B’s daily work = (A+B+C)’s daily work = 1/10

B’s daily work = 1/40 …..(1)

also , 2 times C’s daily work =(A+B)’s daily work

add both side C’s daily work,

3times C’s daily work = (A+B+C)’s daily work = 1/10

C’s daily work = 1/30 ……(2)

Now , A’s daily work

= 1/10-(1/40+1/30)= 1/24

A= 24 days , B=40days , C =30 days

**Also Check Out** **Quantitative Aptitude Quiz for IBPS | RRB – Set 265**