# Quantitative Aptitude Quiz for IBPS | RRB – Set 265

1) there is some profit when an article is sold for Rs 720. However when he same article sold is for rs 420. There is some loss, if the quantum of loss is two times the quantum of profit , find the cost price of article?
a)600
b)621
c)620
d)590

Cp =x
(720-x)2=x-420)
720-x)2=x-420
3x= 1860
X=620

2)A person sells his table at a profit of 25% and the chair at a loss of 20 % but oon the whole he gain Rs 18. On the other hand if he sells the table at a loss of 20% and the chair at a profit of 25 % then he neither gain or nor loss.find the cost price of table and chair.
a)300rs,160rs
b)200rs,150rs
c)200rs,250rs
d)200rs,160rs

X=18 x=25% y=20%
Cost price of table=Xx/x^2-y^2*100
18*25/625-400*100
18*25*100/225= 200rs = cost price of table
Cost price of chair=Xy/x^2-y^2*100
18*20/625-400*100
18*20*100/225 = 160rs = cost price of chair

3)A farmer sold a cow and a calf for rs 760 and got a proft of 10% on the cow and 25% on the calf. If he sells the cow and the calf for rs 767.5 and gets a proft of 25% on the cow and 10% on the calf find the individual cost price of the cow and calf.
a)300,350
b)400,450
c)350,400
d)300,250

Calf=x cow=y (x*125% ) + (y*110% )=760 1.25x+1.1y=760….(1)
(x*110% ) +(y*125% )=767.50 1.1x+1.25y=767.50….(2) 1.25x+1.1y=76000
1.1x+1.25y=767500
X=300 Y=350
Calf-300 cow=350

4)9 kg of rice cost as much as 4 kg of sugar; 14 kg of sugar cost as much as 1.5 kg of tea; 2 kg of tea cost as much as 5 kg of coffee;
find the cost of 11 kg of coffee, if 2.5 kg of rice cost Rs. 12.50.
a)462
b)462
c)462
d)462

9 kg of rice = 4 kg of sugar
14 kg of sugar cost=1.5 kg of tea
2 kg of tea cost=5 kg of coffee
11 kg of coffee cost = ??
2.5 kg of rice= cost Rs. 12.50
12.50*9*14*2*11/2.5*4*1.5*5 = 462

5)The distance between A and B is 80 km. Boat P could travel from point A to B upstream and point B to A downstream in total 30 hours. Boat Q could travel from point A to B upstream and point B to A downstream in total 9 hours. If the speed of boat Q in still water is thrice of boat P in still water, what is the speed of boat Q if speed of current remains constant for both?
a)20 kmph
b)18 kmph
c)28 kmph
d)30 kmph

Let up be speed of boat P in still water, uq be speed of boat Q in still water and vp be speed of current.
According to the question,
80/?? − ?? + 80/ ?? + ?? = 30
80/?? − ?? + 80/?? + ?? = 9
Also it is given uq=3up, vp = vq which is already used.
Then by putting the values and solving both equation
We get speed of boat Q, uq= 18 kmph

6)A boat takes 19 hrs for travelling downstream from point A to point B and coming back to a point C midway between A and B. if the speed of the stream is 4 kmph and the speed of the boat in still water is 14 kmph, what is the distance between A and B?
a)120 ??
b)150 ??
c)180 ??
d)200 ??

According to the question, Speed of boat = 14 kmph
Speed of stream = 4 kmph
Let the distance be x
Therefore upstream speed = 14-4 = 10 kmph
Downstream speed = 14+4 = 18 kmph
Then we have,
(?/2)/10 + ?/18 = 19
?? ??????? ?? ??? ? = 180 ??

7)A man takes 3 hr and 45 minutes to row a boat 15 km with the current in a river and 2 hours 30 minutes to cover a distance of 5 km against the current. Find the ratio of the speed of the boat in still water and the speed of the current?
a)1:5
b)3:2
c)1:3
d)3:1

Time taken to row downstream = 3 hr 45 mins = 15/4 hrs
Downstream speed = 15/15/4 = 4 kmph
Similarly upstream speed = 2 kmph
Ratio = 4+2/(4-2) = 6/2 = 3:1

8)At his usual rowing rate, Sameer rows 12 miles down stream in a river in 6 hrs less than it takes him to travel the same distance upstream. But if he could double his usual rowing rate for his 24 miles round the downstream 12 miles would then take only one hour less than the upstream 12 miles. What is the speed of the current in miles per hours?
a)2/3 miles/hr
b)8/3 miles/hr
c)7/3 miles/hr
d)5/3 miles/hr

According to the question,
12/? + ? + 6 = 12/? − ?
And
12/2? − ? + 1 = 12/2? − ?
By solving above equation,
Then v = 8/3 miles/hr

9)A man row 71/2 kmph in still water. If in a river running at 1.5 km an hour, if takes him 50 min to row to place and back. How far off is the place?
a)1 km
b)5 km
c)6 km
d)3 km

Speed of boat = 7.5 kmph
Speed of stream = 1.5 kmph
?/9+?/6 = 50/60
Then x = 3 km

10)Ravi can row at 5 kmph in still water. If the velocity of the current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place?
a)2400 meters
b)2200 meters
c)2000 meters
d)3600 meters