Quantitative Aptitude Quiz – 89

1. (31.98)² – (35.02)² + (19.03)² = ?² + √255
a) +/- 13
b) +/- 18
c) +/- 9
d) +/- 12

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Ans: d) +/- 12

2. Rahul purchased a house for Rs. 10 lakh. He sold it at 6% loss. With that money he again purchased another house and sold it at a profit of 12%. What is his overall loss/profit?
a) Rs. 54, 600 profit
b) Rs. 51, 800 loss
c) Rs. 52, 800 profit
d) Rs. 51, 900 loss

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Ans: c) Rs. 52, 800 profit 
SP of house = 10,00,000 × 94100
= Rs. 9,40,000
Now, CP of another house = Rs. 9,40,000
And SP of another house = Rs. 10,52,800
Overall profit = Rs. 10,52,800 – Rs. 10,00,000 = Rs. 52,800

3. Ms. Pooja invests 13% of her monthly salary, i.e. Rs. 8554 in Mediclam Policies. Later she invests 23% of her monthly salary on child Education Policies; also she invests another 8% of her monthly salary on Mutual Funds. What is the total annual invested by Ms. Pooja?
a) Rs. 28952
b) Rs. 43428
c) Rs. 347424
d) Rs. 173712

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Ans: c) Rs. 347424 
Let Ms. Pooja’s monthly salary be Rs. x
According to the question,
13% of x = Rs. 8554
=> x = Rs. (8554 * 100)/13 = Rs. 65800
Total monthly investment in percentage
=> 13 + 23 + 8 = 44
Total montly investment = 44% of Rs. 65800
=> (44 * 65800)/100 = Rs. 28952
Total annul investment = Rs. (12 * 28952) = Rs. 347424

4. Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?
a) 5/11
b) 7/11
c) 9/11
d) 6/11

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Ans: d) 6/11
Part filled by A+B+C in 3 min = 3(1/20+1/30+1/10) = 11/20
Part filled by C in 10 min = 3/10
Required ratio = 3/10:11/20 = 6:11
So the solution R in the liquid in the tank after 3 minutes = 6/11

5. 8.5% of 160 – 0.42% of 750 = ?
a) 11.45
b) 12.45
c) 10.45
d) 9.45

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Ans: c) 10.45 
x = 8.5/100 * 160 – 0.42/100 * 750
= 13.6 – 3.15 = 10.45

Directions (6 – 9) : The circle-graph given here shows the spending of a country on various sports during a particular year. Study the graph carefully and answer the questions given below it.

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6. What percent of total spending is spent on Tennis?
a) 12 ½ %
b) 22 ½ %
c) 25%
d) 45%

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Ans: a) 12 ½ %
Percentage of money spend on Tennis = [(45 /360)] X 100% = 12 ½

7. How much percent more is spent on Hockey than that on Golf?
a) 27 %
b) 37 %
c) 37.5 %
d) 75 %

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Ans: d) 75 %
Let the total spending on sports be Rs. x. Then,
Amount spent on Golf = Rs [(36x/ 360 )] = Rs. x/ 10
Amount spent on Hockey = Rs [ ( 63x/360)]= Rs. 7x /40
Difference = Rs. [(7x /40) – (x/10)] = Rs 3x/40
Required percentage = Rs. [ (3x/40)/ x /10) * 100] % = 75%

8. If the total amount spent on sports during the year be Rs. 1,80,00,000 , the amount spent on Basketball exceeds on Tennis by:
a) Rs. 2, 50,000
b) Rs. 3, 60,000
c) Rs.3, 75,000
d) Rs. 4, 10,000

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Ans: a) Rs. 2, 50,000
Amount spent on Basketball exceeds that on Tennis by:
Rs. [ (50 – 45)/ 360) * 1,80,00,000]= Rs. 2,50,000.

9. How much percent less is spent on Football than that on Cricket?
a) 22 2/9 %
b) 27 %
c) 33 1/3 %
d) 37 1/7 %

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Ans: c) 33 1/3 %
Let the total spending on sports be Rs. x. Then,
Amount spent on Cricket = Rs [( 81/360) * x ) = Rs. 9x/40
Amount spent on Football = Rs [( 54/360) *x] = Rs. 3x/20
Difference = Rs. [ ( 9x /40) – ( 3x/20) ] = Rs. 3x/40
Required percentage = Rs. [ (3x/40/ 9x/40) * 100)] % = 33 1/3 %

10. Train X starts from point A for point B at the same time that train Y starts from B to A. Point A and B are 300 km apart. The trains are moving at a constant speed at least at 25 km/h. The trains meet each other 3 hours after they start. If the faster trains takes at least 2 more hours to reach the destination. By which time will the slower train have definitely reached its destination? (Ignoring the length of trains in crossing)
a) 4 hours after the start
b) 7.5 hours after the start
c) 6 hours after the start
d) 7 hours after the start

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Ans: b) 7.5 hours after the start 
Let Speed of train x = a kmph
& Speed of train y = b kmph
a + b = 300/3 = 100 kmph
The faster trains takes be atleast = (3+2) hr = 5 hr
i.e speed of slower train = 40 kmph
i.e time = 300/40 = 7.5 hr


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