Quantitative Aptitude Quiz – 87

1. If a shopkeeper sales a cow at 16(2/3) % profit and a buffalo at 12(1/2)% loss, he gains Rs. 30 in whole transaction. If he sales a cow at 12.5 % loss and the buffalo at 16(2/3)% profit he neither gains nor losses. Find sum of their prices ?
a) 620
b) 720
c) 725
d) 625
e) None of these

Click here to View Answer
Ans: (b) Rs. 720
Let the price of Cow and Buffalo be X and Y respectively.
Cow sold at 16(2/3)% profit = X+16(2/3)% of X = 350X/300 = 7X/6.
Also buffalo at 12(1/2)% loss = X-12(1/2)% of X = 175X/200 = 7X/8.
== > 7X/6 + 7Y/8 = X+Y+30
== > 28X + 21Y = 24X+24Y+720
== > 4X – 3Y = 720…(i)
Also, 7X/8 + 7Y/6 = X+Y
== > -3X + 4Y = 0 …(ii)
Adding (i) and (ii), we get
X+Y = 720

2. A person sold his watch for Rs 24. If the percentage of his loss was equal to the cost price, then the watch would have cost him
a) Rs. 40
b) Rs. 60
c) Rs. 50
d) Rs. 80
e) None of these

Click here to View Answer
Ans: e) None of these
SP=24
Let CP be X
Loss% = X
(X-24)*100/X = X
X^2 – 100X +2400= 0
X= 60 or 40
Hence, None of these

3. In a two digit number the digit at unit’s place is less than twice the digit at ten’s place by 1. And the difference between the number obtained by interchanging its digits and the original number is 50% of the number obtained by adding 1 in original number. What is the original number?
a) 46
b) 57
c) 35
d) 68
e) None of these

Click here to View Answer
Ans: 7. (c) 35
Let the number be 10x+y
Now, ATQ, we have following conditions
(i) y = 2x-1
(ii) 9y-9x = 50%(10x+y+1) = > 9y-9x = 1/2(10x+y+1)
== > 18y-18x = 10x+y+1
== > 17y-28x = 1
Solving (i) and (ii), we get x=3 and y=5
Thus, Number = 10×3+5 = 35

4. A sum of money amounts to Rs. 2380 in four years at simple interest. If the rate of interest be raised by 30%, the sum amounts to Rs. 2584 during the same period. What is the rate of interest ?
a) 8%pa
b) 10%pa
c) 12%pa
d) 13%pa
e) Cannot be determined.

Click here to View Answer
Ans: b) 10%pa
Let the sum be X and Rate of interest be r% pa
== > 2380-X = X*r*4/100…(i)
Also, 2584-X = X*1.3r*4/100…(ii)
2380-X/2584-X = 1/1.3
== > 3094-1.3X = 2584-X
== > 510= 0.3X = = > X= 1700
== > 2380-1700 = 1700*r*4/100
== > r = 680/68 = 10%pa

5. A person sold a ball and a bat together for Rs.1966 there by making a profit of 16% on ball and 12% on bat. By selling them together for Rs.2024, he would have made a profit of 12% on ball and 16% on bat. What is the cost price of ball and bat together ?
a) 1600
b) 1650
c) 1700
d) 1750
e) 1800

Click here to View Answer
Ans: d) 1750
1.16X + 1.12Y = 1966
1.12X + 1.16Y = 2024
Solving both we get
X= 150, Y = 1600
X+Y = 1750

di11

1. The ratio of investment of UP to the state of AP in power sector is—
a) 10 : 13
b) 13 : 10
c) 10 : 21
d) 21 : 10

2. What is the ratio between the investment in IT of AP and in other of UP ?
a) 65 : 63
b) 182 : 95
c) 63 : 65
d) 95 : 182

3. The total investment in Road sector by these states is—
a) 800 cr
b) 720 cr
c) 760 cr
d) 700 cr

4. The FDI in cinema sector in Delhi is what per cent less than that in Kerala in others ?
a) 40%
b) 80%
c) 50%
d) 60%

5. FDI in Maharashtra in Telecom sector is what per cent of that in AP in IT sector ?
a) 42
b) 32
c) 62
d) 22

Click here to View Answer
ANSWERS WITH EXPLANATIONS

di1ans


Check out our latest videos on youtube