In Quantitative Aptitude Section, Boats & Streams is very important. Increase your speed by practicing repeatedly.
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 Total Questions : 20
 Time : 20 Minutes
 Each Question Carries One Mark
 Topic : Boats & Streams
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Question 1 of 20
1. Question
Category: Quantitative AptitudeIf a man can swim downstream at 6kmph and upstream at 2kmph his speed in still water is
Correct
Speed downstream a = 6 km ph
Speed upstream b = 2kmph
Speed in still water = ½ (a+b) kmph
= ½ (6+2)
= 8/2 = 4kmph
speed in still water = 4kmphIncorrect
Speed downstream a = 6 km ph
Speed upstream b = 2kmph
Speed in still water = ½ (a+b) kmph
= ½ (6+2)
= 8/2 = 4kmph
speed in still water = 4kmph 
Question 2 of 20
2. Question
Category: Quantitative AptitudeA man can row upstream at 8kmph and downstream at 12kmph the speed of the stream is
Correct
Speed downstream a = 12kmph
Speed upstream b = 8 kmph
Speed of the stream = ½ (ab) = ½ (128)
= 4/2 = 2 kmph
speed of the stream = 2kmphIncorrect
Speed downstream a = 12kmph
Speed upstream b = 8 kmph
Speed of the stream = ½ (ab) = ½ (128)
= 4/2 = 2 kmph
speed of the stream = 2kmph 
Question 3 of 20
3. Question
Category: Quantitative AptitudeIf Anshul rows 15km upstream and 21km downstream taking 3 hours each time, then the speed of the stream is
Correct
speed upstream = 15/3 =5
b = 5km/hr
speed of the stream = ½ (ab) km/hr
= ½ (75)
= 1 km/hr
speed of the stream = 1km/ hrIncorrect
speed upstream = 15/3 =5
b = 5km/hr
speed of the stream = ½ (ab) km/hr
= ½ (75)
= 1 km/hr
speed of the stream = 1km/ hr 
Question 4 of 20
4. Question
Category: Quantitative AptitudeA man rows 750m in 675 seconds against the stream and returns in 7 ½ minutes. How rowing speed in still water is?
Correct
Speed in still water = ½ (a+b)
= ½ (750/450 + 750/675 ) m /sec
= ½ (750/450 + 750/675 ) x 18/5 km/hr
= ½ (5/3 + 30/31) x 18/5 km/hr
= 4.7 km/hrIncorrect
Speed in still water = ½ (a+b)
= ½ (750/450 + 750/675 ) m /sec
= ½ (750/450 + 750/675 ) x 18/5 km/hr
= ½ (5/3 + 30/31) x 18/5 km/hr
= 4.7 km/hr 
Question 5 of 20
5. Question
Category: Quantitative AptitudeIf a boat goes 7km upstream in 42 minutes and the speed of the stream is 3kmph, then the speed of the boat in still water is
Correct
Speed upstream = 7/42 km/min = 7/42 x 60 km/ hr
i.e, b=10 km/hr
Speed of the stream = 3km/hr
½ (ab) = 3
½ (a10) = 3 ==> a10=6 ==>a=16 km/hr
Speed of the boat in still water
= ½ (a+b)
= ½ (16+10)
= 26/2 = 13km/hrIncorrect
Speed upstream = 7/42 km/min = 7/42 x 60 km/ hr
i.e, b=10 km/hr
Speed of the stream = 3km/hr
½ (ab) = 3
½ (a10) = 3 ==> a10=6 ==>a=16 km/hr
Speed of the boat in still water
= ½ (a+b)
= ½ (16+10)
= 26/2 = 13km/hr 
Question 6 of 20
6. Question
Category: Quantitative AptitudeIf a man rows at 6kmph is still water and 4 : 5kmph against the current, then his along the current is
Correct
Let the rate along the current i.e, speed upstream b
Speed downstream b be x km/hr
a = 4.5km/hr
== > ½ (a+b) = 6
½ (4.5 + x ) = 6
4.5 + x = 12
x = 12 – 4.5 = 7.5
Speed along the current = 7.5 km/hrIncorrect
Let the rate along the current i.e, speed upstream b
Speed downstream b be x km/hr
a = 4.5km/hr
== > ½ (a+b) = 6
½ (4.5 + x ) = 6
4.5 + x = 12
x = 12 – 4.5 = 7.5
Speed along the current = 7.5 km/hr 
Question 7 of 20
7. Question
Category: Quantitative AptitudeA man can row 9 1/3 kmph in still water and finds that it takes him thrice as much time to row up than as to row down the same distance in the river. The speed of the current is
Correct
Let man’s rate upstream be x km/hr. Then his rate downstream is 3 x km/hr
Speed in still water = 9 1/3 = 28/3 km/hr
i.e, ½ (a+b) = 28/3 km/hr
½ (x+3x) = 28/3
2x = 28/3 ==> x = 28/ 2 x 3 = 14/3 km/hr
Rate upstream b = 14/3 km/hr and
Rate downstream a = 14/3 x 3 = 14 km/hr
Speed of the current = ½ (ab) = ½ (14 – 14/3)
= ½ (4214/3) = 28/6 = 4 2/3 km/hrIncorrect
Let man’s rate upstream be x km/hr. Then his rate downstream is 3 x km/hr
Speed in still water = 9 1/3 = 28/3 km/hr
i.e, ½ (a+b) = 28/3 km/hr
½ (x+3x) = 28/3
2x = 28/3 ==> x = 28/ 2 x 3 = 14/3 km/hr
Rate upstream b = 14/3 km/hr and
Rate downstream a = 14/3 x 3 = 14 km/hr
Speed of the current = ½ (ab) = ½ (14 – 14/3)
= ½ (4214/3) = 28/6 = 4 2/3 km/hr 
Question 8 of 20
8. Question
Category: Quantitative AptitudeA boat takes 4hours for traveling downstream from point A to point B and coming back to point A upstream. If the velocity of the stream is 2kmph and the speed of the boat in still water is 4kmph, what is the distance
between A and B?Correct
Time taken by boat to travel upstream and downstream = 4 hours
Velocity of the stream, ½ (ab) = 2km/hr
ab = 4km/hr —— > 1
velocity of the boat in still water = ½ (a+b) = 4km/hr
a+b = 8 km/hr —— > 2
solving 1 x 2 we get a = 6 km/hr b = 2km/hr
let the distance between A and B be x km
x / 2 + x / 6 = 4 ==> 3x + x / 6 = 4 ==> 4x = 24 ==> x = 6
Distance between A and B = 6kmIncorrect
Time taken by boat to travel upstream and downstream = 4 hours
Velocity of the stream, ½ (ab) = 2km/hr
ab = 4km/hr —— > 1
velocity of the boat in still water = ½ (a+b) = 4km/hr
a+b = 8 km/hr —— > 2
solving 1 x 2 we get a = 6 km/hr b = 2km/hr
let the distance between A and B be x km
x / 2 + x / 6 = 4 ==> 3x + x / 6 = 4 ==> 4x = 24 ==> x = 6
Distance between A and B = 6km 
Question 9 of 20
9. Question
Category: Quantitative AptitudeSpeed of a boat in standing water is 9kmph and the speed of the stream is 1 : 5kmph. A man rows to a place at a distance of 10.5 km and comes back to the starting point. The total time taken by him is
Correct
Speed in still water = ½ (a+b) = 9 kmph
= a+b = 18 ——— > (i)
Speed of the stream = ½ (ab) = 1.5 kmph
= ab = 3 kmph —— > (ii)
Solving (i) and (ii) gives a = 10.5km/hr ; b=7.5 kmph
Total time taken by him = 105/10.5 + 105/7.5 = 24 hoursIncorrect
Speed in still water = ½ (a+b) = 9 kmph
= a+b = 18 ——— > (i)
Speed of the stream = ½ (ab) = 1.5 kmph
= ab = 3 kmph —— > (ii)
Solving (i) and (ii) gives a = 10.5km/hr ; b=7.5 kmph
Total time taken by him = 105/10.5 + 105/7.5 = 24 hours 
Question 10 of 20
10. Question
Category: Quantitative AptitudeA man rows to a place 48km distant and back in 14 hours. He finds that he can row 4km with the stream in the same time as 3km against the stream. The rate of the stream is
Correct
Suppose he moves 4km downstream in x hours
Then, downstream a = 4 /x km/hr
Speed upstream b = 3/x km/hr
48 / 4 /x + 48 / 3/x = 14
x/4 + x/3 = 14/48 = ¼
3x + 4x / 12 = ¼ ==> 7x X 4 = 12 ==> x = 3/7
a=28/3 km/hr; b = 7km/hr
Rate of stream = ½ (28/3 – 7 )
= 7/6 = 1.1 km/hrIncorrect
Suppose he moves 4km downstream in x hours
Then, downstream a = 4 /x km/hr
Speed upstream b = 3/x km/hr
48 / 4 /x + 48 / 3/x = 14
x/4 + x/3 = 14/48 = ¼
3x + 4x / 12 = ¼ ==> 7x X 4 = 12 ==> x = 3/7
a=28/3 km/hr; b = 7km/hr
Rate of stream = ½ (28/3 – 7 )
= 7/6 = 1.1 km/hr 
Question 11 of 20
11. Question
Category: Quantitative AptitudeA man rows to a place 48km distant and back in 14 hours. He finds that he can row 4km with the stream in the same time as 3km against the stream. The rate of the stream is
Correct
Suppose he moves 4km downstream in x hours
Then, downstream a = 4 /x km/hr
Speed upstream b = 3/x km/hr
48 / 4 /x + 48 / 3/x = 14
x/4 + x/3 = 14/48 = ¼
3x + 4x / 12 = ¼ ==> 7x X 4 = 12 ==> x = 3/7
a=28/3 km/hr; b = 7km/hr
Rate of stream = ½ (28/3 – 7 )
= 7/6 = 1.1 km/hrIncorrect
Suppose he moves 4km downstream in x hours
Then, downstream a = 4 /x km/hr
Speed upstream b = 3/x km/hr
48 / 4 /x + 48 / 3/x = 14
x/4 + x/3 = 14/48 = ¼
3x + 4x / 12 = ¼ ==> 7x X 4 = 12 ==> x = 3/7
a=28/3 km/hr; b = 7km/hr
Rate of stream = ½ (28/3 – 7 )
= 7/6 = 1.1 km/hr 
Question 12 of 20
12. Question
Category: Quantitative AptitudeA man swims at 16 kmph in still water. If the river is flowing at 5 kmph, it takes 10 hours to go upstream than to go to the same direction downstream. How far is the place? Correct
Let the distance be x km
Then, x/16 – 5 – x/16 + 5 = 10
x/11 – x/21 = 10
21x – 11x/21 X 11 = 10
∴ 21 X 11 = 231 kmIncorrect
Let the distance be x km
Then, x/16 – 5 – x/16 + 5 = 10
x/11 – x/21 = 10
21x – 11x/21 X 11 = 10
∴ 21 X 11 = 231 km 
Question 13 of 20
13. Question
Category: Quantitative AptitudeA boat runs at 25 kmph along the stream and 10 kmph against the stream. Find the ratio of the speed of the boat in still water to that of the speed of the stream. Correct
Speed along the stream = 25 kmph
Speed against the stream = 10 kmph
Now, the speed of the boat in still water = 25 + 10/2 = 17.5 kmph
Speed of stream = 25 – 10/2 = 7.5 kmph
∴ Reqd ratio = 17.5 : 7.5 = 7 : 3Incorrect
Speed along the stream = 25 kmph
Speed against the stream = 10 kmph
Now, the speed of the boat in still water = 25 + 10/2 = 17.5 kmph
Speed of stream = 25 – 10/2 = 7.5 kmph
∴ Reqd ratio = 17.5 : 7.5 = 7 : 3 
Question 14 of 20
14. Question
Category: Quantitative AptitudeA boat covers a distance of 56 km downstream in 10 hours. To cover the same distance upstream, the boat takes 4 hours longer. What is the speed of the boat in still water? Correct
Speed of the boat downstream = 56/10 = 5.6 kmph
Speed of the boat upstream = 56/14 = 4 kmph
Speed of the boat in still water = 5.6 + 4/2 = 9.6/2 = 4.8 kmphIncorrect
Speed of the boat downstream = 56/10 = 5.6 kmph
Speed of the boat upstream = 56/14 = 4 kmph
Speed of the boat in still water = 5.6 + 4/2 = 9.6/2 = 4.8 kmph 
Question 15 of 20
15. Question
Category: Quantitative AptitudeA man rows to a place 210 km away and comes back to the starting point. If the speed of the stream is 3 kmph and the speed of the boat in still water is 18 kmph, then what is the total time taken by him? Correct
Total time = 210/(18 + 3) + 210/(18 – 3)
= 210/21 + 210/15 = 10 + 14 = 24 hoursIncorrect
Total time = 210/(18 + 3) + 210/(18 – 3)
= 210/21 + 210/15 = 10 + 14 = 24 hours 
Question 16 of 20
16. Question
Category: Quantitative AptitudeThe speed of a man in still water is 7.5 kmph and the rate of flow of water is 2.5 kmph. He takes 30 hours to row to a place and back. What is the distance between these two places? Correct
Let the distance between the two places be D km
Speed of the man downstream = 7.5 + 2.5 = 10 kmph
Speed of the man upstream = 7.5 – 2.5 = 5 kmph
Let the time taken to go downstream be t_{1} and upstream be t_{2}
Distance D is 10t_{1} = 5t_{2}
∴ t_{2} = 2t_{1} ———— > (i)
t_{1} + t_{2} = 30 ——— > (ii)
Solving (i) and (ii), we get
t_{1} = 10 hours
t_{2} = 20 hours
∴ Distance = 10t_{1} = 10 X 10 = 100 kmIncorrect
Let the distance between the two places be D km
Speed of the man downstream = 7.5 + 2.5 = 10 kmph
Speed of the man upstream = 7.5 – 2.5 = 5 kmph
Let the time taken to go downstream be t_{1} and upstream be t_{2}
Distance D is 10t_{1} = 5t_{2}
∴ t_{2} = 2t_{1} ———— > (i)
t_{1} + t_{2} = 30 ——— > (ii)
Solving (i) and (ii), we get
t_{1} = 10 hours
t_{2} = 20 hours
∴ Distance = 10t_{1} = 10 X 10 = 100 km 
Question 17 of 20
17. Question
Category: Quantitative AptitudeA boat takes a total time of 11 hours and 15 minutes to travel a distance of 60 km upstream and 60 km downstream together. If the speed of the boat in still water is 12 kmph, what is the speed of the current? (in kmph) Correct
Let the speed of the current be x kmph
Then, download speed = 12 + x
Upstream speed = 12 – x
Now, 60/ 12 +x + 60/ 12 – x = 11 + 15/60 = 11¼ = 45/4
60 X 12 – 60x + 60 X 12 + 60x/144 – x^{2} = 45/4
1440/144 – x^{2} = 45/4
32/144 – x^{2} = ¼
128 = 144 – x^{2}
x^{2} = 144 – 128 = 16
∴ x = 4 kmphIncorrect
Let the speed of the current be x kmph
Then, download speed = 12 + x
Upstream speed = 12 – x
Now, 60/ 12 +x + 60/ 12 – x = 11 + 15/60 = 11¼ = 45/4
60 X 12 – 60x + 60 X 12 + 60x/144 – x^{2} = 45/4
1440/144 – x^{2} = 45/4
32/144 – x^{2} = ¼
128 = 144 – x^{2}
x^{2} = 144 – 128 = 16
∴ x = 4 kmph 
Question 18 of 20
18. Question
Category: Quantitative AptitudeThe speed of a boat in still water is 20 kmph. If it can travel 52 km downstream and 28 km upstream in the same time, the speed of the stream is Correct
Let the speed of the stream be x kmph
Speed downstream = (x + 20) kmph
Speed upstream = (20 – x) kmph
∴ 52/ (20 + x) = 28/ (20 – x)
13/20 + x = 7/20 – x
260 – 13x = 140 + 7x
20x = 120
∴ x = 6 kmphIncorrect
Let the speed of the stream be x kmph
Speed downstream = (x + 20) kmph
Speed upstream = (20 – x) kmph
∴ 52/ (20 + x) = 28/ (20 – x)
13/20 + x = 7/20 – x
260 – 13x = 140 + 7x
20x = 120
∴ x = 6 kmph 
Question 19 of 20
19. Question
Category: Quantitative AptitudeA boat takes 3 hours to travel from place A to place B downstream and back from B to A upstream. If the speed of the boat in still water is 4 kmph. What is the distance between the two places? Correct
Let the distance from place A to B be x km and the speed of the current be y km/hr
Now, x/4 + y + x/4 – y = 3
4x – xy + xy + 4x/(4 – y) (4 + y) = 3
3(16 – y^{2}) = 8x
48 – y^{2} = 8x
So, we can’t find the distances.Incorrect
Let the distance from place A to B be x km and the speed of the current be y km/hr
Now, x/4 + y + x/4 – y = 3
4x – xy + xy + 4x/(4 – y) (4 + y) = 3
3(16 – y^{2}) = 8x
48 – y^{2} = 8x
So, we can’t find the distances. 
Question 20 of 20
20. Question
Category: Quantitative AptitudeThe total time taken by a boat travelling from X to Y and Y to X is 2 hours. The speed of the boat is 12 kmph and the distance between X and Y is 9 km. What is the speed of the current? Correct
Let the speed of the current be x kmph
Then, 9/12 + x + 9/12 – x = 2
9(12 – x + 12 + x)/144 – x^{2} = 2
24 X 9/144 – x^{2} = 2
144 – x^{2} = 108
x^{2} = 36
∴ x = 6 kmphIncorrect
Let the speed of the current be x kmph
Then, 9/12 + x + 9/12 – x = 2
9(12 – x + 12 + x)/144 – x^{2} = 2
24 X 9/144 – x^{2} = 2
144 – x^{2} = 108
x^{2} = 36
∴ x = 6 kmph