Quantitative Aptitude Quiz for SBI PO | IBPS | RBI – Set 104

1. By Selling a article for Rs. 8260, A merchant has a profit of 18%, but due to fall of demand he sell at only 2/3 of the profit %. Find the new Selling Price.
a) 7000
b) 7500
c) 7800
d) 7840

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Ans: d) 7840

New Selling price = (8260*112) /118 = 7840

2. A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is:
a) 3/91
b) 1/22
c) 5/24
d) 2/91

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Ans: d) 2/91

Probability of all of them are red= 5C3/15C3=2/91

3. The difference between the compound interest and the simple interest on a certain sum of money at 10% per annum for 2 years is Rs. 2.50. Find the sum.
a) Rs. 350
b) Rs. 275
c) Rs. 250
d) Rs. 325

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Ans: c) Rs. 250

Sum= 2.50(100/10²)=250Rs

4. If the circumference of one circle is 5/2 times that of other , how many times the area of smaller circle is the bigger one ?
a) 4/25
b) 25/24
c) 25/4
d) 24/25

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Ans: c) 25/4

5*2πr/2* 2πr = 5r/2r

Ratio of bigger to smaller=π(5r)²/π(2r)² =25/4

5. There are 4 red balls, 5 blue balls and 3 green balls in a jar. 2 balls are drawn at random. Find the probability that both are either green or red.
1) 2/31
2) 2/33
3) 1/22
4) 3/22

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Ans: 4) 3/22

Probability of both are either green or red= 3C2 + 4C2/12C2 = 3/22

Directions (6 – 9): Study the following line graph to answer these questions.

Railway Time Schedule of an Express Train X Running Between City A and City H

a – Arrival of train, d – Departure of train

A, B, C, D, E, F, G and H – Cities through which the train runs.

a-d – Indicates stoppage/halting of the train at the city station.

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6. The average speed of the train maintained between two successive stations was maximum between
a) E – F
b) F – G
c) G – H
d) both G – H and F – G
e) None of these

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Ans: d) both G – H and F – G

The average speed maintained by the train between different stations E and F 106 km in 5/4 h =((106×4) )/5 = 84.8 kmph
Similarly, average speed between F and G = 176 km
In 2h = 88 km/h
Between G and H = (110*4)/5 = 88 km/h

7. Between how many pairs of consecutive stations does the speed run below the overall average speed of the entire trip?
a) 4
b) 1
c) 3
d) 2
e) None of these

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Ans: d) 2

Over all average speed of the entire trip : 860 km in 11 hr 25 min
i.e. (685/137) h =(860*12)/137 = 75.3 km/h
Average speed maintained by the train between station
A and B 140 km in 12/3h = (140*3)/5 = 84 km/h
B and C 91 km in 4/3 h=91*(3/4) km/h=68.25 km/h
C and D 149 km in 103/60=(149*60)103 =86.8 km/h
D and E 88 km in 4/3 h=(88*3)/4=66 km/h
E and F = 84.8 km, FG = 88km/h, GH = 88km/h
Hence, for two stations it runs below the overall average speed

8. If the train stops at each city for 30% more time that what it is at the moment, then at what time will it reach the city H after departing from City A as per schedule?
a) Data insufficient
b)17 : 03
c)16 : 41
d)16 : 58
e) None of these

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Ans: c)16 : 41

The train stops at station B for 3 min more
The train stops at station C for 36 sec more
The train stops at station D for 1.5 min more
The train stops at station E for 3 min more
The train stops at station F for 4.5 min more
In all the trains stops 15 min and 36 s more
The train will reach city H after departing from city A at 16h, 40 min, 36 sec i.e., 16h , 41 min approx

9. The train begins its onward journey from City A and it is extended to beyond City H to a City M due to some unavoidable reason. The train starts its return journey immediately after it reached City M. The train returns with a speed of 90 km/h without any stoppages in between and reaches City A at 2 : 25 am. Find the distance between City H and City M.
a) 40 km
b) 90 km
c) 70 km
d) 59 km
e) None of these

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Ans: d) 59 km

Let the distance between city H and city M be x km.
Time taken by the trains from H and A (return)
860/90 = 86/9h
Given, the trains reaches city A (return) at 2.25 am
i.e, at 26.25(hours)
The train reaches at H (return)
At = (26+25/60)-86/9= (16+31/36)h
Time taken from H to M and back
(607/36) – (192/12)= 4/3h
Since the train runs from G to H 88km/h, therefore the train runs 88km/h from city H to city M also. Also speed between city M and city H = 90kmph
x/88+x/90=4/3
x = 59 km

10. If x is less than y by 25% then y exceed x by:
a) 33.33%
b) 25%
c) 75%
d) 66.66%
e) None of these

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Ans: a) 33.33%

Let y be 100
x = 75
Required percent = (25*100)/75 = 33.33%


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