Quantitative Aptitude Quiz for RBI | IBPS – Set 157

1) A and B together can complete a work in 3 days. They start together but after 2 days, B left the work. If the work is completed after two more days, B alone could do the work in?
A)5days
B)6days
C)9days
D)10days

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Answer B)6 days
(A+B)’s one day’s work = 1/3 part;
(A+B) works 2 days together = 2/3 part;
Remaining work = 1-(2/3) = 1/3 part;
1/3 part of work is completed by A in two days;
Hence, one day’s work of A = 1/6;
Then, one day’s work of B = 1/3-1/6=1/6;
So, B alone can complete the whole work in 6 days.

2) A can complete a piece of work in 18 days, B in 20 days and C in 30 days, B and C together start the work and forced to leave after 2 days. The time taken by A alone to complete the remaining work is?
A)10 days
B)12 days
C)15 days
D)16 days

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Answer C)15days
(B+C)’s 2 days work = 2*(1/20+1/30) = 2*(3+2/60) = 1/6 part.
Remaining work = 1-1/6 = 5/6 part;
A’s one day’s work = 1/18 part;
Time taken to complete the work,
= (5/6)/(1/18) days; Hence, Time taken to complete the work
= (5/6)*18 = 15 days.

3)Working 5 hours a day, A can Complete a work in 8 days and working 6 hours a day, B can complete the same work in 10 days. Working 8 hours a day, they can jointly complete the work in?
A)3days
B)4days
C)4.5days
D)5.4 days

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Answer A) 3days
Working 5 hours a day, A can complete the work in 8 days i.e.
= 5*8 = 40 hours;
Working 6 hours a day, B can complete the work in 10 days i.e.
= 6*10 = 60 hours;
(A+B)’s 1 hour’s work,
= (1/40+1/60)
=(3+2)/120
= 5/120
= 1/24 =Hence, A and B can complete the work in 24 hours i.e. they require 3 days to complete the work.

4) Ganga and Saraswati, working separately can mow field in 8 and 12 hours respectively. If they work in stretches of one hour alternately. Ganga is beginning at 9 a.m., when will the moving be completed?
A)6pm
B)6:30pm
C)5pm
D)5:30pm

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Answer B) 6:30 pm
Whenever, workers are working alternatively on one work, we take 2 as 1 unit.
In this case, we take 2 hours as 1 unit.
Part of the field moved by Ganga and Saraswati in 2 hours (1 unit) = 1/8 + 1/12 = 5/24;
Time taken to complete the work,
= 1/(5/24) = 24/5 unit of time;
Then actual time taken by them to complete the work,
= 24*2/5 = 9.5 hours.
The work starts at 9 a.m. then it will complete at 6:30 pm.

5) A complete 7/10 of a work in 15 days, then he completed the remaining work with the help of B in 4 days. In how many day A and B can complete entire work together?
A)10(1/2) days
B)12(2/3) days
C)13(1/3) days
D)8(1/4) days

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Answer C)13(1/3) days

6) In how many ways can 10 examination papers be arranged so that the best and the worst papers never come together?
A)8*9!
B)8*8!
C)7*9!
D)9*8!

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Answer A) 8*9!
No. of ways in which 10 paper can arranged is 10! Ways.
When the best and the worst papers come together, regarding the two as one paper, we have only 9 papers.
These 9 papers can be arranged in 9! Ways.
And two papers can be arranged themselves in 2! Ways.
No. of arrangement when best and worst paper do not come together,
= 10!- 9!.2! = 9!(10-2) = 8.9!

7) In how many ways 4 boys and 3 girls can be seated in a row so that they are alternate?
A)144
B)288
C)12
D)256

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Answer A)144
Let the Arrangement be,
B G B G B G B
4 boys can be seated in 4! Ways.
Girl can be seated in 3! Ways.
Required number of ways,
= 4!*3! = 144.

8) In how many ways can 8 Indians and, 4 American and 4 Englishmen can be seated in a row so that all person of the same nationality sit together?
A)3! 4! 8! 4!
B)3! 8!
C)4! 4!
D)8! 4! 4!

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Answer A)3! 4! 8! 4!

9)Three gentlemen and three ladies are candidates for two vacancies. A voter has to vote for two candidates. In how many ways can one cast his vote?
A)9
B)30
C)36
D)15

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Answer D)15
There are 6 candidates and a voter has to vote for any two of them.
So, the required number of ways is,
= 6C2 = 6!/2!*4! = 15

10)Find the number of triangles which can be formed by joining the angular points of a polygon of 8 sides as vertices?
A)56
B)24
C)16
D)8

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Answer A) 56
A triangle needs 3 points.
And polygon of 8 sides has 8 angular points.
Hence, number of triangle formed,
= 8C3 = (8*7*6)/(1*2*3)
= 56.

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