Quantitative Aptitude Quiz for IBPS | IPPB – Set 186

1)On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get?
1) 24
2) 18
3) 15
4) Cannot be determined
5) None of these

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Answer 3)15
; Required number of sweets=((112-32)×6)/32=(80×6)/32=15

2)An order was placed for supply of carpet of breadth 3 metre, and the length of the carpet was 1.44 times of breadth. Subsequently the breadth and length were increased by 25 and 40% respectively. At the rate of Rs. 45 per square metre, what would be the increase in the cost of the carpet?
1) Rs1,020.60
2) Rs398.80
3) Rs437.40
4) Rs583.20
5) None of these

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Answer 3) Rs437.40
; Breadth of carpet=3 m
∴ Length of carpet=3×1.44=4.32
∴ Area of carpet=3×4.32=12.96 m^2
New length=4.32×140/100=6.048 m
New breadth=3×125/100=3.75 cm
New area=6.048×3.75=22.68 m^2
Increased area=22.68-12.96=9.72 m^2
∴ Required increased cost=9.72×45=Rs437.40

3)in a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water? (Weight in gm)
1) 75%
2) 88%
3) 90%
4) 100%
5) None of these

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Answer 5) None of these
Water in 60 gm mixture=60×75/100=45 gm
Again, water in (60+15) gm mixture=45+15=60 gm
∴ Required percentage=60/75×100=80%

4)What would be the compound interest obtained on an amount of Rs. 20,000/- at the rate of 15 p.c.p.a. after 4 years?
1) Rs14,980.125
2) Rs19,680.125
3) Rs16,780.125
4) Rs18,980.125
5) None of these

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Answer 1)Rs14,980.125
Required compound interest=20000[(1+15/100)^4-1]=Rs14,980.125

5)A 280-m-long train takes 20 sec to cross a person who is going in the same direction with the speed of 6 km/h. After crossing that person, the train can reach next station in 45 min. How long will that person take to reach the station after being crossed by train?
1) 7 hr 3 min
2) 6 hr 3 min
3) 7 hr 30 min
4) 7 hr 50 min
5) 6 hr 30 min

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Answer 1) 7 hr 3 min
Speed of the person = 6 km/hr
= 6 * 5/18 = 5/3 m/s
Let the speed of train be x m/s
20 = 280/(x – 5/3)
x – 5/3 = 14
x = 47/3m/s
Now the distance covered by train in 45 minutes.
= 47/3 * 60 * 45 = 42300
Time taken by person to cover the distance
= 42300/(6*5/18) = 25380 sec
25380/(60 * 60) = 7 hours 3 minutes

Directions: What value should come in the place of question mark (?) in the following questions?

6)99 50/51 * 561 = ?
1) 57089
2) 54089
3) 56089
4) 56099
5) 56182

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Answer 3) 56089
? = (100 – 1/51) * 561 = 56089

7)114 % of 250 + 124 % of 450 = ?
1) 833
2) 843
3) 923
4) 823
5) 943

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Answer 2)843
? = 114/100 * 250 + 124/100 * 450
= 285 + 558 = 843

8)1/(21/5) + 1/(32/5) = ?
1) 41/105
2) 44/105
3) 47/110
4) 43/107
5) 43/105

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Answer 5) 43/105
? = 5/21 + 6/35
= (25 + 18)/105 = 43/105

9)6, 9, 15, 21, ? , 39
1) 27
2) 29
3) 31
4) 33
5) 35

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Answer 4)33

10)1, 1, 3, 9, 13, 65, 71, ? , 505
1) 197
2) 297
3) 397
4) 497
5) 597

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Answer 4)497

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