Quantitative Aptitude Quiz for IBPS | IPPB – Set 175

1)In the examination a candidate must get 2/5th marks to pass, out of total marks.Shiyam appeared in the exam ang got 198 marks and still failed by 36 marks.The maximum mark is?
A)560
B)610
C)585
D)480

Click to View Answer
Answer C) 585
2x = 198+36 = 234
Max = 234*5/2 = 585

2)If 4 is added to the numerator of a fraction it becomes 1/3 and if 3 is added to the denominator it becomes 1/6 then find the numerator and denominator is?
A)5/26
B)25/4
C)6/17
D)5/27

Click to View Answer
Answer D)5/27
5/27 = 9/27 = 1/3
5/30 = 1/6

3)(6084)1/2 = ?
A)78
B)±78
C)72
D) )±72

Click to View Answer
Answer B)±78

4)What is the difference between the CI and SI on Rs.6500 at the rate of 4 pcpa in 2 yrs ?
A)9.4
B)10.4
C)15.4
D)14.5

Click to View Answer
B)10.4
SI = 6500*4*2/100 = 520
CI = 6500*(104/100)*(104/100) = 7030.4 = 530.4
530.4 – 520 = 10.4

5)Find the CI on Rs.4500 at 4% pa for 2 yrs compounded half yearly(approx) ?
A)963
B)369
C)639
D)360

Click to View Answer
Answer C)639
CI = P [(1+(r/100)n – 1] = 4500[(1+2/100)4 – 1
= 4500[ (102*102*102*102/100*100*100*100) – 1] = 4500[1.082 – 1] = 4500*0.082 = 369

6)The least number of complete years in which a sum of money put out at 10% CI will be more than doubled is?
A)8yrs
B)6yrs
C)4yrs
D)7yrs

Click to View Answer
AnswerA)8yrs
P(110/100)n > 2P
(11/10) n > 2P
1.1*1.1*1.1*1.1*1.1*1.1*1.1*1.1 = 2.14 > 2
N = 8

7)A sum of money doubles itself at CI in 10yrs. In how many yrs will it become 4 times ?
A)10yrs
B)20yrs
C)15yrs
D)22yrs

Click to View Answer
Answer B)20yrs
P(1+(R/100))10 = 2P
1+(R/100)10 = 2
(1+(R/100))n = 4 = 22
2*10 = 20yrs

8)At what rate of CI pa will a sum of Rs.1000 becomes Rs.1040.4 in 2yrs ?
A)2%
B)1%
C)1.5%
D)3%

Click to View Answer
Answer A)2%
1000*(1+(R/100)) 2 = 1040.4
(1+(R/100)) 2 = 1040.4/1000
(1+(R/100)) 2 = 10404/10000 = (102/100) 2
R = 2%

9)The average weight of 40 students in a class is 75 kg. By mistake the weights of two students are read as 74 kg and 66 kg respectively instead of 66 kg and 54 kg. Find the corrected average weight of the class?
A) 73.50 kg
B) 74.50 kg
C) 75.50 kg
D) 76.50 kg

Click to View Answer
Answer b) 74.50 kg
Weight of 40 students = 40*75
new weight = 40*75 – 74 – 66 + 66 + 54 = 40*75 – 20
so new average =( 40*75 – 20)/40 = 74.50 kg

10)The average weight of 40 balls is 5 grams. When the weight of the basket is added to the weight of balls, the average increased by 0.5 grams. Find the weight of the basket?
A) 20.5 gm
B) 22.5 gm
C) 25.5 gm
D) 28.5 gm

Click to View Answer
Answer c) 25.5 gm
Explanation :
(40*5 + B)/41 = 5.5 (B is the weight of basket)

Check out our latest videos on youtube